Explanation:
Let 
are the number of turns in primary and secondary coil of the transformer such that,
A resistor R connected to the secondary dissipates a power 
For a transformer, 
...............(1)
The power dissipated through the secondary coil is :
.............(2)
Let 
are the new number of turns in primary and secondary coil of the transformer such that,
New voltage is :
...............(3)
So, new power dissipated is 
So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.
Answer:
The transverse wave will travel with a speed of 25.5 m/s along the cable.
Explanation:
let T = 2.96×10^4 N be the tension in in the steel cable, ρ = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.
then, if V is the volume of the cable:
ρ = m/V
m = ρ×V
but V = A×L , where L is the length of the cable.
m = ρ×(A×L)
m/L = ρ×A
then the speed of the wave in the cable is given by:
v = √(T×L/m)
= √(T/A×ρ)
= √[2.96×10^4/(4.49×10^-3×7860)]
= 25.5 m/s
Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.
Answer:
B. Both electric fields and forces ...
Explanation:
First of all we know about the ionic bond that the attraction b/w two atoms the atom which lose electrons is become cation and have positive sing which one get electrons it become ionic. so in such sitivation the sodium lose one electons "that's why sodium has 1+ charge in Nacl chemacal bond."
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