NaBr < H3O+1 = OH-1 < Na^+1 = Br^-1 < H2O
<span>Least is NaBr (100% dissolved so no NaBr remains, only Na^+1 and Br^-1 </span>
<span>H2O yields 10^-7 M H3O^+1 and 10^-7 M OH^-1 (Kw = 1x10^-14 = [H3O+][OH-] </span>
<span>Na^+1 and Br^-1 will bothe be 0.1 M </span>
<span>H2O is slightly less that 1000 g / L in a 0.1 M NaBr solution, so its concentration is about 55.5 M</span>
I assume there is a typo in the equation. It is H2O instead of H2I.
The ratio of H2 and O2 that react with each other is 2:1. To find out the grams of H2, we need to first find out the moles of O2 and H2.
Moles of O2 = mass of O2/molar mass of O2 = 192g/32g/mol = 6 mol. Therefore, the moles of H2 = 6mol *2 = 12 mol.
So the mass of H2 that reacts with O2 = moles of H2 * molar mass of H2 = 12 mol * 2 g/mol = 24 g
This is done by reducing each number by a common factor for each formula.
C3H6O6- all can be divided by 3 -> CH3O3 (you don't have to put a 1 for C, only if your teacher requests it. It is generally understood if not written)
H2O2- all can be divided by 2 -> H1O1 (had to put the 1's bc of the unintended language)
C8H8S2- all can be divided by 2 -> C4H4S
P5O15- all can be divided by 5- PO3
*****it is important to note that <em>all </em>numbers in the molecular formula are divided by the same thing to reduce them. decimals are <em>never </em>used in empirical formulas, only whole numbers.*****
Answer:
B
Explanation:
I don't know how to explain this but you get it
Answer:
electromagnetic wave
Explanation:
Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate.
