Are there electrical appliances at home that don't use transformers?If yes, state a few examples of them.

Please help me Calculate the total energy stored in the capacitor

Neko [114]

La fórmula: P = W/t ó W = P x t. donde:

P = potencia

W = trabajo

t = tiempo

Otra fórmula de potencia es: P= I x V

Proceso de carga de un capacitor - condensador

Una fórmula muy importante que también hay que tener en cuenta es: V = q/C que indica que el voltaje es proporcional a la carga que hay en un condensador.

De la fórmula de potencia P= I x V y considerando que la corriente es constante (corriente continua), entonces la potencia es proporcional al voltaje. Si el voltaje aumenta en forma lineal, la potencia aumentará igual. Ver el siguiente diagrama.

Como la potencia varía en función del tiempo, no se puede aplicar la fórmula W = P x t, para calcular la energía transferida. Pero observando el gráfico, se ve que esta energía se puede determinar midiendo el área bajo la curva de la figura.

Energía Almacenada en un Condensador - Capacitor

El área bajo la curva es igual a la mitad de la potencia en el momento “t”, multiplicada por “t”.

Entonces: W = (P x t) / 2. Pero se sabe que P = V x I. Si se reemplaza esta última fórmula en la anterior se obtiene: W = (V x I x t) / 2, y como I x t = CV = Q, entonces para saber cuanta energía (W) hay en un condensador usamos una de las siguientes fórmulas:

W = (CV2/2) julios

W = (QV/2) julios

W = (Q2/2C) julios

, donde:

W = Trabajo (Energía) en julios

C = Capacidad en faradios

V = voltaje en voltios en los extremos del condensador

Q = carga del condensador

3 0

3 years ago

Read 2 more answers

A charged box (m=445 g, ????=+2.50 μC) is placed on a frictionless incline plane. Another charged box (????=+75.0 μC) is fixed i

victus00 [196]

The concept required to perform this exercise is given by the coulomb law.

The force expressed according to this law is given by

$F= \frac{kqQ}{r^2}$

Where,

$k = 8.99 * 10^9 N m^2 / C^2.$

q = charges of the objects

r= distance/radius

Our values are previously given, so

$q= 2.5*10^{-6}C\\Q= 75*10^{-6}C\\r=0.59$

Replacing,

$F=\frac{kqQ}{r^2}$

$F= \frac{(8.99 x 10^9)(2.5*10^{-6})(75*10^{-6})}{0.59^2}$

$F= 4.8423N$

The force acting on the block are given by,

$F-mgsin\theta = ma$

$a = \frac{F-mgsin\theta}{m}$

$a = \frac{4.8423-(0.445)(9.8)sin(35)}{0.445}$ $a = 10.31m/s^2$

Therefore the box is accelerated upward.

3 0

3 years ago

Difference betwwen Acclerat<br>ion and retradation

BartSMP [9]

I’m pretty sure one increases just straight up velocity and the other is kind of a deceleration

6 0

3 years ago

Does the number of particles change as the substance changes its state?

Leviafan [203]

Particles stay the same unless there is a chemical change whether the matter is solid, liquid or gas. ... When substances change state there is no change in mass so if 100 g of ice is melted 100g of water are formed this will boil to form 100g of steam (this is called "conservation of mass").

4 0

3 years ago

Consider the reaction X mc022-1.jpg Y + 2Z . If the molar solubility of X is multiplied by 2, the value of Ksp will be multiplie

Alex777 [14]

X -> Y + 2Z

So there are 2 different particles. 1 mol of X produces 1 mol of Y and 2 moles of Z.

Kps = [Y] [Z]^2

We will call “s” (solubility) the molarity of X

So the molarity of Y+ is also “s” (same number)

And the molarity of Z is “2s” (twice as much)

Kps = s*(2s)^2 = s*4s^2=4s^3

If s is multiplied by 2:

Kps = 4*(2s)^3=4*2^3*s^3=4*8*s^3

So Kps is multiplied by 8.

4 0

4 years ago

Are there electrical appliances at home that don't use transformers?If yes, state a few examples of them. ​

Are there electrical appliances at home that don't use transformers?If yes, state a few examples of them.