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Andrew [12]
3 years ago
7

Look at the two vectors below:

Physics
1 answer:
Komok [63]3 years ago
5 0

a) Draw their beginnings coming out of one point

b) Use addition in parallelogram.

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A large, simple pendulum is on display in the lobby of the United Nations building. If the pendulum is 18.5 m in length, what is
zhannawk [14.2K]

Answer:

     t = 1,144 s

Explanation:

The simple pendulum consists of an inextensible string with a mass at the tip, the angular velocity of this is

     w = √( L / g)

The angular velocity is related to the frequency and period

     w = 2π f

      f = 1 / T

     w = 2π / T

Let's replace

     2π / T = √ (L / g)

     T = 2π √ (g / L)

Let's calculate

     T = 2π √ (9.81 / 18.5)

     T = 4,576 s

The definition of period in the time it takes the ball to come and go to a given point (a revolution) in our case we go from the end to the middle point that is a quarter of the path

     t = T / 4

     t = 4,576 / 4

     t = 1,144 s

6 0
4 years ago
Tory has a mass of 40kg. She sleds down a hill that has a slope of 25 degrees. what is the component of her weight that is along
Fudgin [204]

1.7 x 10^2 N

or 166 N

First you find the vertical component of the weight, which is 9.8*40, (g*m), which is 392 N. You then find the angle between that and the slope, which is 90-25, which is 65. You then multiply the vertical weight by cos(65), to find the component of that that is parallel to the slope. You get 165.666 N

3 0
4 years ago
Study the scenario.
Otrada [13]

If no other forces act on the object, according to Newton’s first law, the spacecraft will continue moving at a constant velocity, assuming that a planet or something with large mass doesn’t cross its path. Forces are not required to continue the motion of an object on a frictionless plane at a constant rate.

7 0
3 years ago
Read 2 more answers
A Cessna aircraft has a lift off speed of 147 km/h. What minimum constant acceleration does this require if the aircraft is to b
netineya [11]

Answer:

The acceleration is  a =51945 \ km/h^2

Explanation:

From the question we are told that

   The lift up speed is  v  = 147 \  km/h

    The distance covered for the take off run is s =  208 m = 0.208 \ km

Generally from kinematic equation we have that

      v^2 = u^2 + 2as

Here u is the initial  speed of the aircraft with value 0 m/ s give that the aircraft started from rest

So  

    147^2 = 0^2 + 2* a* 0.208

=>  a =51945 \ km/h^2

6 0
3 years ago
A box, compressing a spring by 4 m, is loaded and ready. Moments later the 8.0 kg box has been launched with
Mrac [35]

Answer:

50 N/m

Explanation:

Elastic energy = kinetic energy

EE = KE

½ kx² = ½ mv²

½ k (4 m)² = ½ (8.0 kg) (10.0 m/s)²

k = 50 N/m

3 0
3 years ago
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