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Kaylis [27]
4 years ago
6

Can someone help me answer this please

Mathematics
2 answers:
Inga [223]4 years ago
7 0

Answer:

19 degrees

Step-by-step explanation:

Firlakuza [10]4 years ago
4 0

Answer: 19 degrees

Step-by-step explanation:

<FOE is the central angle of an arc of 52 degrees and is thus 52 degrees.  Then by supplementary angles <COD is 71 degrees and angle BOA is thus also 71 degrees.  Then by supplementary angles <BOC is 19 degrees and arc BC is thus also 19 degrees.

Hope it helps <3

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Help with #2 it has to do with number 1 that is the polygon you need to find the area of it.
Katena32 [7]
Okay, it's the equation to how find area any other way. A=L×W

This means *picture above*

So then you count over each line meaning 1.
This means L=9 and a 1/2. Since its in between the 2 an 3 on the x-axis.
Now for W or width. It equals 3 since you can count 2 lines and one either ends of the polygon is 1/2 each this creates one when added together.

All you do from there is multiply 9 and 3. This should give you A=area.

8 0
3 years ago
Select the choice that translates the following verbal phrase correctly to algebra: (2 points)
fgiga [73]
I think its c. because m-7 is difference and + 15 is increasing
6 0
3 years ago
√48a^4 b^5 c^3 d simplify and keep it in radical form
Morgarella [4.7K]
I will assume the square root extends all the way across.

\sqrt{48a^4b^5c^3}

\sqrt{2^4\cdot3\cdot a^4b^5c^3}

\sqrt{(2^2)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4)^2\cdot3\cdot(a^2)^2\cdot(b^2)^2\cdot b\cdot c^2\cdot c}

\sqrt{(4\cdot a^2 \cdot b^2 \cdot c)^2\cdot3\cdot b\cdot c}

4\cdot a^2\cdot b^2\cdot c\sqrt{3\cdot b\cdot c}

\boxed{4a^2b^2c\sqrt{3bc}}






3 0
4 years ago
Please answer this I'm confused with it
lianna [129]

Answer:

x intercepts are (4,0) and (-6,0)

axis of symmetry is x=-1

vertex is (-1,-25)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Evaluate (64^-1/2)^-2/3
Ira Lisetskai [31]

Answer:

4

Step-by-step explanation:

We'll do two things here.  First remember that when a number is raised to an exponent, and the result is raised to another exponent, you can simply multiply those exponents and apply them to the base.  So we can multiply -1/2 and -2/3, giving us 1/3, which is what we'll raise 64 to.

The other thing to remember is that a fractional exponent is the same as a root of that base.  So raising a number to the power of 1/3 just means we want the cube root of that number.

Applying those and we get:

(64^{-\frac{1}{2}})^{-\frac{2}{3}}\\= 64^{(-\frac{1}{2} \times -\frac{2}{3})}\\= 64^{\frac{1}{3}}\\= 4

6 0
3 years ago
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