Electrons have a negative charge. True False
1 answer:
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Answer : The standard enthalpy of formation of methanol is, -238.7 kJ/mole
Explanation :
Standard formation of reaction : It is a chemical reaction that forms one mole of a substance from its constituent elements in their standard states.
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The formation reaction of will be,
The intermediate balanced chemical reaction will be,
(1)
(2)
(3)
Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, we get :
(1)
(2)
(3)
The expression for enthalpy of formation of will be,
Therefore, the standard enthalpy of formation of methanol is, -238.7 kJ/mole
Balanced chemical equation is :
It is given that the equation is in equilibrium.
We need to find what will happen if we add more is added .
By Le Chatelier's principle :
Changing the concentration of a chemical will shift the equilibrium to the side that would counter that change in concentration.
It means production of the side where content is added will decrease and concentration on other side will increase .
So , more NO would form .
Therefore, option B. is correct.
Hence, this is the required solution.