Answer:
ithink it is c but i dont my ghess
Explanation:
i want to do thos for the points tbh
<span>pv=nrt; Pressure and moles are constant.
p=nr(150k)/.5 L; Pressure initially
After temp change
pv=nrt; What is volume?
v=nr(350k)/p; p is constant so we can substitute from above
v=nr(350k)/(nr(150k)/.5 L))
v=350/150/.5 L
v=4.66 liters</span>
Answer:
Q = -33.6kcal .
Explanation:
Hello there!
In this case, according to the equation for the calculation of the total heat of reaction when a fixed mass of a fuel like ethane is burnt, we can write:

Whereas n stands for the moles and the other term for the enthalpy of combustion. Thus, for the required total heat of reaction, we first compute the moles of ethane in 3 g as shown below:

Next, we understand that -337.0kcal is the heat released by the combustion of 1 mole of ethane, therefore, to compute Q, we proceed as follows:

Best regards!