1) Decomposition reactions. In this type of reaction, a compound is broken down into simpler compounds.
Option B is a decomposition reaction
B) ____ KClO3 → ____ KCl + ____ O2
srry the pic is not clear......
l cant see it.....
Answer:
What is the empirical formula of the compound?
Explanation:
When the relative masses of elements in a hydrocarbon are given, it is possible to use this information to obtain the empirical formula by dividing the given masses of each element by the relative atomic masses of the element. The lowest ratio is now used to divide through to obtain the empirical formula of the compound.
The empirical formula only shows that ratio of atoms of each element present in the compound. From the information provided, the empirical formula of the compound is CH2. Hence the answer.
Answer:
Element Symbol Mass Percent
Cuprum Cu 66.464%
Sulfur S 33.537%
Explanation:
I got this out of my module, sorry if it's wrong but i am pretty sure 97% this is correct!
CaBr2(s) Ca+2(aq)+2Br-(aq) which means, <span>Solid is turning into free ions so entropy is increasing .</span>
