260g explanation in the pic
A semiconductor conducts electricity at high temperatures, but not at low temperatures. At high temperatures, metalloids act like metals and conduct electricity.
Explanation:
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Answer:
You need 0.702g of ferrous ammonium sulfate hexahydrate to prepare the desired solution.
Explanation:
First, you want to prepare 250.0mL of a 400.0ppm of Fe²⁺ (That is mg/L, w/v):
0.250L * (400mg / L) = 100mg Fe²⁺ = 0.1g Fe²⁺
Molar mass of Fe is 55.845g. moles are:
0.1g Fe²⁺ * (1mol / 55.845g) =
<h3>1.79x10⁻³ moles Fe²⁺</h3>
The Fe²⁺ comes from ferrous ammonium sulfate hexahydrate, as 1 mole of this salt contains 1 mole of Fe²⁺, moles of the salt you need are:
1.79x10⁻³ moles Fe(NH₄)₂(SO₄)₂.6H₂O.
To convert these moles to grams you must use molar weight, MW, thus:
1.79x10⁻³ moles Fe(NH₄)₂(SO₄)₂.6H₂O * (392.14g / 1mol) =
<h3>You need 0.702g of ferrous ammonium sulfate hexahydrate to prepare the desired solution.</h3>
1.66 M is the concentration of the chemist's working solution.
<h3>What is molarity?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
In this case, we have a solution of Zn(NO₃)₂.
The chemist wants to prepare a dilute solution of this reactant.
The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.
We want to know the concentration of this diluted solution.
As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:
=
(1)
and we also know that:
n = M x 
If we replace this expression in (1) we have:
x
=
x 
Where 1, would be the stock solution and 2, the solution we want to prepare.
So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is
:
4.93 x 210 = 620 x
= 1.66 M
This is the concentration of the solution prepared.
Learn more about molarity here:
brainly.com/question/19517011
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