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2 years ago

CaC2 + 2H2O ➞ C2H2 + Ca(OH)2

Chemistry

1 answer:

Paraphin [41]2 years ago

3 0

Answer:

A. 0.5 mole of Ca(OH)₂.

B. 4.37 moles of H₂O.

Explanation:

The balanced equation for the reaction is given below:

CaC₂ + 2H₂O —> C₂H₂ + Ca(OH)₂

Next, we shall determine the mass of CaC₂ that reacted and the mass of C₂H₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of CaC₂ = 40 + (12×2)

= 40 + 24

= 64 g/mol

Mass of CaC₂ from the balanced equation = 1 × 64 = 64 g

Molar mass of C₂H₂ = (12×2) + (2×1)

= 24 + 2

= 26 g/mol

Mass of C₂H₂ from the balanced equation = 1 × 26 = 26 g

SUMMARY:

From the balanced equation above,

64 g of CaC₂ reacted with 2 moles of H₂O to produce 26 g of C₂H₂ and 1 mole of Ca(OH)₂.

A. Determination of the number of mole of Ca(OH)₂ produced by the reaction of 32.0 g of CaC₂.

From the balanced equation above,

64 g of CaC₂ reacted to produce 1 mole of Ca(OH)₂.

Therefore, 32 g of CaC₂ will react to produce = (32 × 1)/64 = 0.5 mole of Ca(OH)₂.

Thus, 0.5 mole of Ca(OH)₂ were obtained from the reaction.

B. Determination of the number of mole of H₂O needed to produce 56.8 g C₂H₂.

From the balanced equation above,

2 moles of H₂O reacted to produce 26 g of C₂H₂.

Therefore, Xmol of H₂O will react to produce 56.8 g C₂H₂ i.e

Xmol of H₂O = (2 × 56.8)/26

Xmol of H₂O = 4.37 moles

Thus, 4.37 moles of H₂O is needed for the reaction.

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When a base reacts with an acid to form a salt and water molecule, it is known as a neutralization reaction. The general equation follows:

$HX+BOH\rightarrow BX+H_2O$

The chemical equation for the reaction of calcium hydroxide and nitric acid follows:

$Ca(OH)_2(aq)+2HNO_3(aq)\rightarrow Ca(NO_3)_2(aq)+2H_2O(l)$

For (2):

A single displacement reaction is defined as the reaction in which a more reactive metal displaces a less reactive metal from its salt solution. The general chemical equation follows:

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Metal A is more reactive than metal B

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Zinc lies above in the series than lead thus is more reactive and will easily replace lead from its aqueous solution.

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How many grams of FeCo3 will be produced from 57.2g FeCl2

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The Balance Chemical Equation is as follow,

FeCl₂ + Na₂CO₃ → FeCO₃ + 2 NaCl

Step 1: Calculate Mass of FeCl₂ as,

Molarity = Moles ÷ Volume

Solving for Moles,

Moles = Molarity × Volume

Putting Values,

Moles = 2 mol.L⁻¹ × 1.24 L

Moles = 2.48 mol

Also,

Moles = Mass ÷ M.Mass

Solving for Mass,

Mass = Moles × M.Mass

Putting Values,

Mass = 2.48 mol × 126.75 g.mol⁻¹

Mass = 314.34 g of FeCl₂

Step 2: Calculate Mass of FeCO₃ formed as,

According to equation,

126.75 g (1 mole) FeCl₂ produces = 115.85 g (1 mole) FeCO₃

So,

314.34 g of FeCl₂ will produce = X g of FeCO₃

Solving for X,

X = (314.34 g × 115.85 g) ÷ 126.75 g

X = 287.30 g of FeCO₃

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