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likoan [24]
4 years ago
7

Calculate the molarity of 0.289 moles of FeC13 dissolved in 120 ml of solution

Chemistry
1 answer:
yanalaym [24]4 years ago
5 0

Answer:

2.41 M

Explanation:

The molarity is the moles of FeCl3 over the liters of solution. Since you're given mL you need to change it to L which is 0.12 L. 0.289 divided by 0.12 is your answer

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Answer:

Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.

Explanation:

From the given,

Mass of sodium carbonate Na_{2}CO_{3}.XH_{2}O = 8.85 g

Loss mass H_{2}O = 1.28 g

Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g

7.57 g Na_{2}CO_{3} \times \frac{1mol}{106 g} =\frac{0.0714}{0.0714}=1

1.28g H_{2}O \times \frac{1mol}{18 g} =\frac{0.0711}{0.0714}=1

Therefore, the compound has only one water molecule.

Molecular formula of the compound is Na_{2}CO_{3}.H_{2}O an name of the compound is <u>sodium carbonate mono hydrate.</u>

Hence, the type of the compound is Mono hydrate.

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