Answer:
Negative Radicals ---→
1).Flouride = F⁻
2). Chloride = Cl⁻
3) Bromide = Br⁻
4) Iodide = I⁻
5) Sulphate = SO₄²⁻
6) Oxide = O²⁻
7) Nitride = N³⁻
8) Sulphur = S²⁻
9) Carbide = C⁴⁻
10) Hydroxide = OH⁻
11) Nitrate = NO₃⁻
12) Carbonate = CO²⁻
13) Hydrogen Carbonate = HCO₃⁻
14) Sulphate = SO₄²⁻
15).Sulphite = SO₃³⁻
16) Nitrate = NO₃⁻
17)Nitrite = NO₂⁻
18) Hydrogen Sulphite = HSO₃⁻
19) Hydrogen Sulphate = HSO₄⁻
20) Chromate = CrO₄²⁻
There are lot of Radicals which cannot be easily written. Although some of the Important Radicals which are commonly used are mentioned above.
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The balanced chemical reaction is written as:
<span>CH4 (g) + 2 O2 (g) ----> CO2 (g) + 2 H2O (g)
</span>
We are given the amount of water to be produced from the reaction. This amount will be used for the calculations. Calculations are as follows:
12.4 L H2O ( 1 mol / 22.4 L ) ( 1 mol CH4 / 2 mol H2O ) ( 22.4 L / 1 mol ) = 6.2 L CH4
Volume:
2.00 x 11.0 x 11.0 => 242 cm³
mass : 213 g
D = m / V
D = 213 / 242
D = 0.880 g/cm³
Answer B
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Answer:
Due to random assortment and incomplete dominance of alleles.
Explanation:
The bunnies end up with ear thicknesses that are different from one another due to random assortment of alleles during gamete formation according to Mendel.
In addition to random assortment, the allele for thick ear also displayed what is known as incomplete dominance over the allele for thin ear to arrive at an average ear thickness.
Answer:
This question is incomplete, here's the complete question:
<em><u>"Suppose 0.0842g of potassium sulfate is dissolved in 50.mL of a 52.0mM aqueous solution of sodium chromate. Calculate the final molarity of potassium cation in the solution. You can assume the volume of the solution doesn't change when the potassium sulfate is dissolved in it. Round your answer to 2 significant digits."</u></em>
Explanation:
Reaction :-
K2SO4 + Na2CrO4 ------> K2CrO4 + Na2SO4
Mass of K2SO4 = 0.0842 g, Molar mass of K2SO4 = 174.26 g/mol
Number of moles of K2SO4 = 0.0842 g / 174.26 g/mol = 0.000483 mol
Concentration of Na2CrO4 = 52.0 mM = 52.0 * 10^-3 M = 0.052 mol/L
Volume of Na2CrO4 solution = 50.0 ml = 50 L / 1000 = 0.05 L
Number of moles of Na2CrO4 = 0.05 L * 0.052 mol/L = 0.0026 mol
Since number of moles of K2SO4 is smaller than number of moles Na2CrO4, so 0.000483 mol of K2SO4 will react with 0.000483 mol of Na2CrO4 will produce 0.000483 mol of K2CrO4.
0.000483 mol of K2CrO4 will dissociate into 2* 0.000483 mol of K^+
Final concentration of potassium cation
= (2*0.000483 mol) / 0.05 L = 0.02 mol/L = 0.02 M
