Answer:
a) Eₓ = - A y + 2B x
, b) Ey = -Ax –C
, c) Ez = 0
, d) The correct answer is 3
Explanation:
The electric field and the electric power are related
E = - dV / ds
a) Let's find the electric field on the x axis
Eₓ = - dV / dx
dV / dx = A y - B 2x
Eₓ = - A y + 2B x
b) calculate the electric field on the y-axis
Ey = - dV / dy
dV / dy = A x + C
Ey = -Ax –C
c) the electric field on the z axis
dv / dz = 0
Ez = 0
.d) at which point the electric field is zero
Since the electric field is a vector quantity all components must be zero
X axis
0 = = - A y + 2B x
y = 2B / A x
Axis y
0 = -Ax –C
.x = -C / A
We substitute this value in the previous equation
.y = 2B / A (-C / A)
.y = 2 B C / A2
The correct answer is 3
Answer:
I go with D but what you can do is u can read each and choose the one that sounds right Hope this helps
Electric current is the movement of electrons through a wire. Electric current is measured in amperes (amps) and refers to the number of charges that move through the wire per second.
Answer:
Very easy question
For x-component, we use Fₓ = Fcosα
For y-component, we use Fy = Fsinα
The major problem is with angle α.
Here α = 90+30
Because the angle is measured from +ve X-axis.
By putting values if you know co-ratios that how Sin and cos Convert to each other then you have got it.
So for further calculation,
Fₓ = Fcos(90+30) = 25(-sin30)
Fₓ = -25(1/2) = 25/2 = 12.5 - will be eliminate because force in magnitude is not "-ve"
As it is
Fy = Fsin(90+30) = Fcos30
Fy = 25 (√3 /2) = 25√3/2
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