Answer:
1.5024
Explanation:
Draw a diagram. Put the two cells in series. Now draw 3 resistors. Two of them equal 0.26 ohms each. The third one is the lightbulb which is 12 ohms.
R = 0.26 + 0.26 + 12 = 12.52
The bulb has a voltage of 2.88 volts across it. You can get the current from that.
i = E / R
i = 2.88 / 12 =
i = 0.24 amps.
Now you can get the voltage drop across the two cells.
E = ?
R = 0.26
i = 0.24 amps
E = 0.26 * 0.24
E = 0. 0624
Finally divide the 2.88 by 2 to get 1.44
Each cell has an emf of 1.44 + 0.0624 = 1.5024
Answer:
The power will be "3.92×10⁹ Watts". A further explanation is given below.
Explanation:
The given values as per the question,
Rate,
= 8 million kg
Distance,
= 50 m
Gravity,
= 9.8 m/s²
As we know,
The power will be:
⇒ 
On putting the values, we get
⇒ 
⇒ 
Answer:
Newton's Third Law of Motion
Explanation:
Newton's Third Law of Motion which states that, for every action there is an equal but opposite reaction.
This ultimately implies that, in every interaction, there is a pair of forces acting on the two interacting objects.
In this scenario, a ball bounced by a basketball player on the floor bounces back up at her.
According to Newton's Third Law of Motion, the statement above simply means that in every interaction, there is a pair of forces acting on the two interacting objects i.e the ball and floor. The size of the force on the ball equals the size of the force on the floor. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
Hence, the ball bounced by the basketball player on the floor would bounce back in equal magnitude.
Answer:
Net force on the block is 32 N.
Acceleration of the object is 6.4 m/s².
Explanation:
Let the acceleration of the object be
m/s².
Given:
Mass of the block is, 
Force of pull is, 
Frictional force on the block is, 
The free body diagram of the object is shown below.
From the figure, the net force in the forward direction is given as:

Now, from Newton's second law of motion, net force is equal to the product of mass and acceleration. So,

Therefore, the acceleration of the object in the forward direction is 6.4 m/s².