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zhenek [66]
3 years ago
5

If a car is accelerating downhill under a net force 3674 N , what additional force would cause the car to have a constant veloci

ty
Physics
1 answer:
Semenov [28]3 years ago
6 0

Answer:

For the car to move with constant velocity the additional force required is  F__{dg} }=  -3674 \  N

Explanation:

From the question we are told that

  The net force of the car is  F_{net} = 3674 \  N

Generally the total  force acting on the  car is the net force plus the force due to gravity acting in direction of the car (Let denote it as F__{dg})

So the total force acting on the car is mathematically represented as

        F_{net} + F__{dg}} = F

Here this F representing the total force can be mathematically represented as

      F =  ma

Now for constant velocity to be attained, the acceleration of the car will be zero  

So  at constant velocity

       F =  m * 0

=>    F =   0 \  N

So  

     F_{net} + F__{dg}} = 0

=>   F__{dg} }=  -F_{net}

=>   F__{dg} }=  -3674 \  N

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mina [271]

Answer:

t = 103.45 n m

Explanation:

given,

refractive index of cornea = 1.38

refractive index of eye drop = 1.45

wavelength of refractive index = 600 nm

refractive index of eye drop is greater than refractive index of cornea and the air.

Formula used in this case

for constructive interference

2 n t = (m + \dfrac{1}{2})\lambda

At m = 0 for the minimum thickness, so

2\times 1.45 \times t = (0 + 0.5)\times 600

2.9 \times t =300

t =\dfrac{300}{2.9}

t = 103.45 n m

the minimum thickness of the film of eyedrops t = 103.45 n m

6 0
3 years ago
A helicopter ambulance flew from one hospital to another in a straight line. The pilot had to change speed several times due to
Olenka [21]

Answer:

Explanation:

All the rest of the information is extraneous. The only 2 things you have to know are

d = 20 km

t = 8 minutes = 8/60 hours = 0.13333333

So the speed is s = d/t

s = 20/0.1333333 = 150 km/hour

Note: you have not specified what units the speed is. I suppose you could answer 20/8 = 2.5 km/min

4 0
3 years ago
The universe was 5 percent its current size when light left objects observed now at redshift of ______________
Nuetrik [128]

The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.

  • The Universe was 5 percent its current size when light left objects now at redshift of <u>19</u>.

Reasons:

The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;

\displaystyle \frac{a}{a_0}  =\mathbf{ \frac{1}{1 + z}}

Where;

a₀ = The current size of the Universe

a = The size of the early Universe = 5% of a

Therefore;

\displaystyle \frac{a}{a_0}  =5\% = 0.05=  \frac{1}{1 + z}

\displaystyle 0.05  = \frac{1}{1 + z}

0.05 + 0.05·z = 1

\displaystyle z = \mathbf{ \frac{1 - 0.05}{0.05} } = 19

  • The redshift is of the observed light is, z = <u>19</u>

Learn more here:

brainly.com/question/14459434

brainly.com/question/3654558

4 0
2 years ago
An 11.0 -W energy-efficient fluorescent lightbulb is designed to produce the same illumination as a conventional 40.0-W incandes
yarga [219]

The amount or cost that the user of the energy-efficient bulb save during 100h of use will be $0.319.

<h3>How to calculate the cost?</h3>

For the 11.0W bulb, it should be noted that the value will be:

= 11.0 × 100 × (1/1000) × 0.110

= $0.121

The 40W bulb will be:

= 40 × 100 × (1/1000) × 0.110

= $0.44

Therefore, the amount that will be saved will be:

= $0.44 - $0.121

= $0.319

Learn more about cost on:

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6 0
2 years ago
If a cross country runner covers a distance of 347 meters in 134 seconds what is her average speed?
a_sh-v [17]
347÷134=2.589552239 meters per second

2.589552239×60= 155.3731343 meters per hour

155.3731343 meters per hour= 0.096544389701642 miles per hour

hopefully this was right.
6 0
4 years ago
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