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3 years ago

8

Billy pulls his friend Sue on a sled at a constant velocity with a horizontal force of 200 N. The weight of the sled and Sue is

400 N. Which way will the sled move if Billy suddenly starts to pull with a force of 600 N?

1 answer:

Nezavi [6.7K]3 years ago

6 0

Pulls would be the logical answer.

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A positively charged particle has a velocity in the negative z direction at point P. The magnetic force on the particle at this

REY [17]

Answer:

When reviewing the correct answer is A

Explanation:

The magnetic force is given by the expression

F = qv xB

where the bold letters indicate vectors, from this expression the module can be calculated

F = = q v b sin θ

the direction of the force is given by the rule of the right hand, for a positive charge the speed held by the thumb, the extended fingers point in the direction of the magnetic field and the palm points the direction of the force

in this case

the speed is in the negative part of the z axis

the force is in the negative direction of the axis and

consequently the magnetizing field is in the positive direction of the x axis

When reviewing the correct answer is A

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3 years ago

A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s afte

lana66690 [7]

Answer: The ball's acceleration is 2.35 m/s2

Explanation: Please see the attachment below

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3 years ago

Read 2 more answers

3. A 0.35 kg puck slides across the ice with an average force of friction of 0.15 N acting on it. It slides 82 m before coming t

sattari [20]

Answer:

Work done is 12.3 J

Explanation:

We have,

Mass of puck, m = 0.35 kg

Force of friction acting on the puck when it slides is 0.15 N

Distance travelled by the puck is 82 m.

It is required to find the work done on the puck. Finally the puck comes to rest and the force of friction is acting on it. It means the applied force is 0.15 N. Work done is given by

$W=Fd\\\\W=0.15\times 82\\\\W=12.3\ J$

The work done on the puck is 12.3 J.

5 0

4 years ago

A ball is hung from a rope, making a pendulum. When it is pulled 5° to the side, the restoring force is 1.0 N. What will be the

Trava [24]

Answer:

restoring force is 2 N

Explanation:

given data

angle pulled = 5°

force = 1 N

pulled = 10°

to find out

restoring force

solution

we know here force

force = m×g×sinθ ..........1

so here θ is very small so sinθ = θ

1 = mg(5)

mg = 1 /5 ..................2

and

now for 10 degree

we know here θ is small so sinθ = θ

so from equation 1

force = m×g×sinθ

put equation 2 here

force = 1/5 × 10

force = 2 N

so restoring force is 2 N

7 0

3 years ago

A rotating wheel requires 3.05-s to rotate through 37.0 revolutions. Its angular speed at the end of the 3.05-s interval is 97.9

Setler79 [48]

Answer:

$\alpha=14.2rad/s^2$

Explanation:

The formula that relates angular displacement with angular acceleration is:

$\Delta \theta=\omega_i t+\frac{\alpha t^2}{2}$

We can obtain $\omega_i$ from the definition of angular acceleration:

$\alpha=\frac{\Delta \omega}{\Delta t}=\frac{\omega_f-\omega_i}{t}$

$\omega_i=\omega_f-\alpha t$

Putting all together:

$\Delta \theta=(\omega_f-\alpha t) t+\frac{\alpha t^2}{2}=\omega_f t-\frac{\alpha t^2}{2}$

Which, since we want the angular acceleration, is:

$\alpha=\frac{2(\omega_f t-\Delta \theta)}{t^2}$

And for our values is:

$\alpha=\frac{2((97.9rad/s)(3.05s)-(37(2\pi rad)))}{(3.05s)^2}=14.2rad/s^2$

5 0

4 years ago