Question

A uniform electric field of magnitude 6.8 × 10 5 N/C points in the positive x direction. (a) Find the electric potential difference (EPD) between the origin (0, 0) and the points (i) (0, 6.0 m), (ii) (6.0 m, 0), and (iii) (6.0m, 6.0 m).

Answer 1

Answer:

i)4080000V

ii)4080000V

iii)5766400v

Explanation:

Hello!

To solve this problem we will use the following steps

1. We will use the equation that defines the distance between two points in order to find the distance from the origin to each of the points that the problem asks for.

$d=\sqrt{x^2+y^2}$

x= horizonalt component

y=vertical component

d=distance

i)

x=0

y=6

$d=\sqrt{0^2+6^2}=6m$

ii)

x=6

y=0

$d=\sqrt{6^2+0^2}=6m$

iii).

x=6

y=6

$d=\sqrt{6^2+6^2}=8.48m$

2.we calculate the voltage at each point using the equation that relates the distance the voltage and the electric field

V=Ed

where

V=EPD= the electric potential difference

E=electric field  magnitude=6.8 × 10^5 N/C.

d=distance

i)

V=Ed=(6.8 × 105 N/C.)(6)=4080000V

ii)

i)

V=Ed=(6.8 × 105 N/C.)(6)=4080000V

iii)

i)

V=Ed=(6.8 × 105 N/C.)(8.48m)=5766400v