An ice hockey puck slides along the ice at 12 m/s.?

1 answer:

6 0

Since we know that..

I = F . ∆t
= m . a . ∆t ( the puck accelerating after the collision with the hockey sticks)
= m . ∆v/∆t . ∆t
= m . ∆v

Solve for m, we get..

m = I / ∆v
= 4 / 12
= 1 / 3 kg or 0.33 kg

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