Question

An ice hockey puck slides along the ice at 12 m/s.?

Answer 1

Since we know that..

I = F . ∆t
= m . a . ∆t ( the puck accelerating after the collision with the hockey sticks)
= m . ∆v/∆t . ∆t
= m . ∆v

Solve for m, we get..

m = I / ∆v
= 4 / 12
= 1 / 3 kg or 0.33 kg