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3 years ago

An ice hockey puck slides along the ice at 12 m/s.?

1 answer:

6 0

Since we know that..

I = F . ∆t
= m . a . ∆t ( the puck accelerating after the collision with the hockey sticks)
= m . ∆v/∆t . ∆t
= m . ∆v

Solve for m, we get..

m = I / ∆v
= 4 / 12
= 1 / 3 kg or 0.33 kg

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How does the temperature of the samples change? Which way does the energy flow?

iogann1982 [59]

Answer: How does the temperature of the samples change?

As the temperature increases, the rate of reaction increases. Particles can only react when they collide. ... Increasing the temperature increases reaction rates because of the large increase in the number of high energy collisions. It is only these collisions that will produce the reaction. Low-temperature experiments prevent denaturation of samples. ... When the temperature of the protein water solution is reduced below the ... The FB peak position does not change but its intensity changes proportionally with variation of intensity of incident radiation.

Which way does the energy flow?

Energy flow in ecosystem occurs by food chain from producer to consumers. ... Then energy is transfered from producers to consumers, called as heterotrophs. Primary consumers are called as herbivores. Herbivores are eaten up by secondary consumers, called as carnivores. Energy flow is always unidirectional. Energy flows progressively from one trophic level to another and cannot revert back. In most of the natural ecosystems, energy comes from the sun, it is trapped by producers and then pass on to successive trophic levels in the form of food.

Explanation:

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3 years ago

Read 2 more answers

3. A hunter shoots a 2 kg arrow accelerating it at 15m/s2 . How much force does this require?

choli [55]

Answer: 30 Newton

Explanation:

Force can be obtained from the product of Mass M and acceleration A. The SI unit of force is Newton.

Thus, Force = MA

Mass of the arrow = 2kg

Acceleration of the arrow = 15m/s2

Force = 2kg x 15m/s2

Force = 30 Newton

Thus, the hunter require a force of 30 newton

6 0

3 years ago

The coefficient of static friction for the tires of a race car is 0.950 and the coefficient of kinetic friction is 0.800. The ca

Arisa [49]

Answer:

speed on planet is 0.5 times of speed on a earth

Explanation:

Given data:

coeeffcient of kinetic friction $= \mu+k =0.8$

friction force is given as

$f_k = \mu_k N$ n -normal force = mg

for max safe speed

fricional force = centripetal force

$\mu_k N = \frac{mV^2}{R}$

$\mu_k m g = \frac{mV^2}{R}$

$v^2 = \mu_k g R$

$v^2 = 0.8\times 2.45 \times 50$ v^2 = 98

v = 9.899 m/sec

therefore maximum speed is $[v max} = 9.899 m/sec$

$\frac{planet\ speed}{ earth\ speed} = \sqrt { \frac{ \mu_k g_p R}{ \mu_k g_e R}}$

$\frac{V_p}{V_e} = \sqrt{\frac{g_p}{g_e}}$

solving for planet speed

$v_p = \sqrt{\frac{2.45}{9.8}} v_e$

$v_p = 0.5 v_e$

speed on planet is 0.5 times of speed on a earth

4 0

3 years ago

Read 2 more answers

The coefficient of kinetic friction between a floor and a box made of wood is µk = 0.13. How far does the box slide if it has an

Jlenok [28]

Answer:

s = 19.23 m

Explanation:

Since, the frictional force is given as:

f = μN = μW

f = μmg ----------- equation (1)

but, from Newton's 2nd Law:

f = ma -------------- equation (2)

comparing equation (1) and equation (2):

ma = μmg

a = μg

here,

a = acceleration of puck

μ = coefficient of static friction = 0.13

g = -9.8 m/s² (negative sign for slowing down of puck)

Therefore,

a = (0.13)(-9.8 m/s²)

a = -1.274 m/s²

Now, using 3rd equation of motion:

2as = Vf² - Vi²

where,

s = distance covered = ?

Vf = Final Velocity = 0 m/s (since, puck finally stops)

Vi = Initial Velocity = 7 m/s

Therefore,

2(- 1.274 m/s²)s = (0 m/s)² - (7 m/s)²

s = (- 49 m²/s²)/(- 2.548 m/s²)

s = 19.23 m

4 0

3 years ago

After the invention of the telescope, astronomers were able to determine that Io is much smaller than Jupiter, is roughly 4.2x10

34kurt

Answer:

a). The mass of Jupiter is $1.873x10^{27}Kg$ .

b). Jupiter has 313.6 Earth masses.

Explanation:

a). Estimate the mass of Jupiter from these observations.

The Universal law of gravitation shows the interaction of gravity between two bodies:

$F = G\frac{Mm}{r^{2}}$ (1)

Where G is the gravitational constant, M and m are the masses of the two objects and r is the distance between them.

For this particular case M is the mass of Jupiter and m is the mass of Io. Since it is a circular motion the centripetal acceleration will be:

$a = \frac{v^{2}}{r}$ (2)

Then Newton's second law ( $F = ma$ ) will be replaced in equation (1):

$ma = G\frac{Mm}{r^{2}}$ (3)

By replacing (2) in equation (3) it is gotten:

$m\frac{v^{2}}{r} = G\frac{Mm}{r^{2}}$ (4)

Therefore, the mass of the Jupiter can be determined if M is isolated from equation (4):

$M = \frac{rv^{2}}{G}$ (5)

But r is the distance between Jupiter and Io ( $4.2x10^{8}m$ ).

However, it is necessary to know the orbital velocity of Io in order to determine the mass of Jupiter.

The orbital velocity is defined as:

$v = \frac{2\pi r}{T}$ (6)

Where T is orbital period of Io ( $1.53x10^{5}s$ ).

$v = \frac{2\pi(4.2x10^{8}m)}{1.53x10^{5}s}$

$v = 17247m/s$

Finally, equation (5) can be used.

$M = \frac{(4.2x10^{8}m)(17247m/s)^{2}}{(6.67x10^{-11}N.m^{2})}$

$M = 1.873x10^{27}Kg$

Hence, the mass of Jupiter is $1.873x10^{27}Kg$ .

b). How many Earth masses does Jupiter have. 

$\frac{1.873x10^{27}Kg}{5.972 x10^{24}kg} = 313.6$

Therefore, Jupiter has 313.6 Earth masses.

8 0

3 years ago