Ask question

Ask question

All categories

3 years ago

10

a bottle lying on the windowsill falls off and takes 4.95 seconds to reach the ground. the distance from the windowsill to the g

round is 120.00 meters. find the time the bottle would take to land if it were to fall the same distance on the moon instead of earth. (note: acceleration due to gravity on the moon is 1/6 that on earth.)

2 answers:

tekilochka [14]3 years ago

8 0

120/4.95 = 24.24 24.24/6 = 4.04 120/4.04 = 29.70 29.70 I think

earnstyle [38]3 years ago

7 0

Answer:

12.3 s

Explanation:

The acceleration due to gravity on the moon is $\frac{g}{6}$ where g (9.8 m/s²) is the acceleration due to gravity on the Earth.

Distance to the ground, s = 120 m

Initial velocity = 0

Use the second equation of motion:

s = u t + 0.5 gt²

⇒ 120.0 m = 0 + 0.5 (1.63 m/s²) t²

$\Rightarrow t = \sqrt{\frac{120}{0.5 \times 1.63}} = 12.13 s$

Thus, it will take more time for a bottle to fall on the Moon than on the Earth off the same height.

You might be interested in

The maximum wavelength that an electromagnetic wave can have and still eject electrons from a metal surface is 459 nm. What is t

spin [16.1K]

Answer:

2.7067 eV

Explanation:

h = Planck's constant = $6.626\times 10^{-34}\ m^2kg/s$

c = Speed of light = $3\times 10^8\ m/s$

$\lambda_0$ = Threshold wavelength = 459 nm

Work function is given by

$W_0=\frac{hc}{\lambda_0}\\\Rightarrow W_0=\frac{6.626\times 10^{-34}\times 3\times 10^8}{459\times 10^{-9}}\\\Rightarrow W_0=4.33072\times 10^{-19}\ J$

Converting to eV

$1\ J=\frac{1}{1.6\times 10^{-19}}\ eV$

$4.33072\times 10^{-19}\ J=4.33072\times 10^{-19}\times \frac{1}{1.6\times 10^{-19}}\ eV=2.7067\ eV$

The work function W0 of this metal is 2.7067 eV

4 0

3 years ago

A proton is initially moving west at a speed of 1.10 106 m/s in a uniform magnetic field of magnitude 0.281 T directed verticall

kifflom [539]

Answer:

so here it will move in circle with radius 4.06 cm

Explanation:

As we know that proton is moving towards west while the magnetic field is vertically upwards

So here the force on the proton must be perpendicular to the velocity

So here we have

$F = q(\vec v \times \vec B)$

so here we have

$F = qvB sin90$

since force is perpendicular to the velocity so here it must be centripetal force

here we have

$\frac{mv^2}{R} = qvB$

so we have

$R = \frac{mv}{qB}$

$R = \frac{(1.66 \times 10^{-27})(1.10 \times 10^6)}{(1.6 \times 10^{-19})(0.281)}$

$R = 4.06 cm$

so here it will move in circle with radius 4.06 cm

8 0

2 years ago

CAN SOMEONE HELP ME

uranmaximum [27]

Oxygen is like a milder form of nitrogen when it comes to its changing forms.

Oxygen becomes a gas when heated above -183 degrees Celsius, and when it is cooled below -183 degrees Celsius, it becomes a liquid.

Just as a bonus, the transition between liquid and solid forms happens when Oxygen is cooled below -218.79 degrees Celsius.

So your answer is "the conversion between the liquid and gaseous states of Oxygen." :)

3 0

2 years ago

Read 2 more answers

Um carro percorre um trecho de 450 km em escalar media do carro

Aleks04 [339]

Average speed of the car is defined as the ratio of total distance and total time

So here we will have

$v_{avg} = \frac{distance}{time}$

now we know that

$distance = 450 km$

time = 5 h

now from above equation we will have

$v = \frac{450 km}{5 h} = 90 km/h$

so the average speed will be 90 km/h

7 0

3 years ago

Ask Your Teacher A coil is formed by winding 260 turns of insulated 16 gauge copper wire (diameter = 1.3 mm) in a single layer o

Liula [17]

Answer:

The resistance is $2.98$ Ω

Explanation:

<u>Data</u>

diameter: $d=1.3mm$ , $d=1.3*10^{-3} m$

Radius: $r=\frac{d}{2} ,r=\frac{1.3*10^{-3} }{2} ,r=6.5*10^{-4} m$

Resistivity constant: $p=1.65*10^{-8}$ Ω $m$

To find Area:

$A=\pi r^{2} \\A=\frac{22}{7} *(6.5*10^{-4} )\\A=1.33*10^{-6} m^{2}$

To find circumference:

$l=260*(2\pi (0.15))\\l=245.04m$

Now we can apply the Resistivity formula:

$R=p\frac{l}{A}$

$R=(1.65*10^{-8} )$ Ω $m*\frac{240.04m}{1.33*10^{-6}m^{2} }$

$R=2.98$ Ω

4 0

3 years ago