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MAVERICK [17]
3 years ago
10

a bottle lying on the windowsill falls off and takes 4.95 seconds to reach the ground. the distance from the windowsill to the g

round is 120.00 meters. find the time the bottle would take to land if it were to fall the same distance on the moon instead of earth. (note: acceleration due to gravity on the moon is 1/6 that on earth.)
Physics
2 answers:
tekilochka [14]3 years ago
8 0
120/4.95 = 24.24 24.24/6 = 4.04 120/4.04 = 29.70 29.70 I think
earnstyle [38]3 years ago
7 0

Answer:

12.3 s    

Explanation:

The acceleration due to gravity on the moon is \frac{g}{6} where g (9.8 m/s²) is the acceleration due to gravity on the Earth.

Distance to the ground, s = 120 m

Initial velocity = 0

Use the second equation of motion:

s = u t + 0.5 gt²

⇒ 120.0 m = 0 + 0.5 (1.63 m/s²) t²

\Rightarrow t = \sqrt{\frac{120}{0.5 \times 1.63}} = 12.13 s

Thus, it will take more time for a bottle to fall on the Moon than on the Earth off the same height.

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What's now called "Conventional current" is thought of as the flow of positive charge, from the battery's positive terminal to its negative one.

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6 0
3 years ago
Read 2 more answers
A vector → A has a magnitude of 56.0 m and points in a direction 30.0° below the negative x axis. A second vector, → B , has a m
MissTica

Answer:

  • The magnitude of the vector \vec{C} is 107.76 m

Explanation:

To find the components of the vectors we can use:

\vec{A} = | \vec{A} | \ ( \ cos(\theta) \ , \ sin (\theta) \ )

where | \vec{A} | is the magnitude of the vector, and θ is the angle over the positive x axis.

The negative x axis is displaced 180 ° over the positive x axis, so, we can take:

\vec{A} = 56.0 \ m \ ( \ cos( 180 \° + 30 \°) \ , \ sin (180 \° + 30 \°) \ )

\vec{A} = 56.0 \ m \ ( \ cos( 210 \°) \ , \ sin (210 \°) \ )

\vec{A} = ( \ -48.497 \ m \ , \ - 28 \ m \ )

\vec{B} = 82.0 \ m \ ( \ cos( 180 \° - 49 \°) \ , \ sin (180 \° - 49 \°) \ )

\vec{B} = 82.0 \ m \ ( \ cos( 131 \°) \ , \ sin (131 \°) \ )

\vec{B} = ( \ -53.797 \ m \ , \ 61.886\ m \ )

Now, we can perform vector addition. Taking two vectors, the vector addition is performed:

(a_x,a_y) + (b_x,b_y) = (a_x+b_x,a_y+b_y)

So, for our vectors:

\vec{C} = ( \ -48.497 \ m \ , \ - 28 \ m \ ) + ( \ -53.797 \ m \ ,  ) = ( \ -48.497 \ m \ -53.797 \ m , \ - 28 \ m \ + \ 61.886\ m \ )

\vec{C} = ( \ - 102.294 \ m , \ 33.886 m \ )

To find the magnitude of this vector, we can use the Pythagorean Theorem

|\vec{C}| = \sqrt{C_x^2 + C_y^2}

|\vec{C}| = \sqrt{(- 102.294 \ m)^2 + (\ 33.886 m \)^2}

|\vec{C}| =107.76 m

And this is the magnitude we are looking for.

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3 years ago
Is being a plat 2 in rainbow 6 siege a good rank?
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Answer:

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Which of Newton’s Laws explains why an object originally moving in a circular path will continue in a straight line path if the
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When object is moving in circular path then if suddenly its force reduced to zero then it will move to straight line

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Plug in the correct numbers into the variables!

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Multiply!

KE = 150,000 / 2

Divide!

KE = 75,000 Newton-meters or Joules!


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