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Roman55 [17]
3 years ago
6

A beaker contains 100.0 mL of a 0.100 M solution of sulfuric acid. When 100.0 mL water is added to this solution, what is the co

ncentration of the diluted sulfuric acid?
Chemistry
1 answer:
OverLord2011 [107]3 years ago
7 0

Answer:

0.05 M.

Explanation:

For the concentrated sulphuric acid,

Number of moles = molar concentration × volume

= 0.1 × 0.1

= 0.01 mol

New volume = 100 + 100 ml

= 200 ml

Concentration of the diluted sulphuric acid = number of moles/volume

= 0.01/0.200

= 0.05 M

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3 years ago
Use the information below to explain why the atomic radius decreases down a group.
notsponge [240]

Answer:

Detail is given below

Explanation:

Atomic radii trend along group:

As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

In A we can see that there is one positive charge and force of attraction is 2.30×10⁻⁸ N and distance is 0.10 nm

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What is the pH of a sample with [OH-] = 2.5 x 10-11 M?
sveticcg [70]

Answer:

The pH of the sample is 3,4.

Explanation:

We calculate the pOH from the formula pOH = -log (OH-). We know that for all aqueous solutions: pH + pOH = 14, and from there we clear pH:

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pH + pOH = 14

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pH=14 -10,60

<em>pH=3,4</em>

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3 years ago
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