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Viefleur [7K]
3 years ago
11

What volume of 0.126 M HCl is needed to neutralize 2.96g of Mg(OH)2?

Chemistry
1 answer:
notka56 [123]3 years ago
3 0
The reaction equation is Mg(OH)2 + 2HCl = MgCl2 + H2O. The mol number of Mg(OH)2 is 2.96/58=0.051 mol. So we need 0.051*2=0.102 mol HCl to neutralize. The volume is 0.102/0.126=0.810 L =810 mL.
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a solution with a transmittance of 0.44 is analyzed in a spectrophotometer with 6% stray light. calculate the absorbance reporte
IgorLugansk [536]

The absorbance reported by the defective instrument was 0.3933.

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S = fraction of stray light = 6%= 6/100 = 0.06

α= 1, ideal case

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Tm = T+S(α-T)

now, T= Tm-S/ 1-S = 0.44-0.06/ 1-0.06 = 0.404233

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brainly.com/question/17088180

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3 0
1 year ago
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Answer:

339kJ

Explanation:

Given parameters:

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Initial temperature of steam  = 100°C

Final temperature of water  = 100°C  

Unknown:

Quantity of heat that must be removed to condense the steam = ?

Solution:

The heat involved here is a latent heat because there is no change temperature. The process is just a phase change.

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Insert the parameters and solve;

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7 0
3 years ago
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