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sineoko [7]
3 years ago
6

If the compound below is oxidized, the resulting product is ___. Select one: a. methane and propane b. butanal c. butanoic acid

d. butane
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
7 0

The complete question is

If the compound below is oxidized, the resulting product is ___.

the compound given is Butanal

Select one:

a. methane and propane

b. butanal

c. butanoic acid

d. butane

Answer:

C. Butanoic Acid

Explanation:

When Butanal is oxidized using reagents like KMnO4, Tollens reagent etc.

When Aldehyde is oxidized corresponding Carboxylic Acid is produced

 Butanal →  Butanoic Acid

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How much hcl must be added to a liter of buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate to result in a buffe
yaroslaw [1]

For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a  result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol

<h3>What is the result in a buffer ph of 4. 01?</h3>

Generally, the equation for the pH   is mathematically given as

pH=pKa+logsalt/acid

Generally, the equation for the Chemical Reaction   is mathematically given as

HCl+CH3CooNa---->NaCl+CH3OOH

Therefore

4.01=4.74+log\frac{0.8-x}{1.3+x}

-0.52=log\frac{0.8-x}{1.3+x}

x=0.313mol

In conclusion, The moles of HCl required is

x=0.313mol

Read more about Chemical Reaction

brainly.com/question/6876669

8 0
3 years ago
g What volume (mL) of the partially neutralized stomach acid was neutralized by NaOH during the titration? (portion of 25.00 mL
Pani-rosa [81]

The question is incomplete, here is the complete question:

What volume (mL) of the partially neutralized stomach acid having concentration 2M was neutralized by 0.01 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)

<u>Answer:</u> The volume of HCl neutralized is 0.125 mL

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl (Stomach acid)

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=2M\\V_1=?mL\\n_2=1\\M_2=0.01M\\V_2=25mL

Putting values in above equation, we get:

1\times 2\times V_1=1\times 0.01\times 25\\\\V_1=\frac{1\times 0.01\times 25}{1\times 2}=0.125mL

Hence, the volume of HCl neutralized is 0.125 mL

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4 years ago
A 250mL sample of air at STP contains approximately 52.5mL of O2. What is the percentage of oxygen in the air
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3 years ago
How many energy levels does sulfur have?<br> A. 2<br> B. 3<br> C. 4<br> D. 14
Karolina [17]
Its electronic confuguration is 2.8.6 so it occupies 3 shells.
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4 years ago
If a rock contains rounded grains of sediments, what can you tell about that rock?
Zielflug [23.3K]

Answer:

sedimentary rock

Explanation:

sediment + rock

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