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Gennadij [26K]
3 years ago
14

A 616 g block is released from rest at height h0 above a vertical spring with spring constant k = 540 n/m and negligible mass. t

he block sticks to the spring and momentarily stops after compressing the spring 23.3 cm. how much work is done (a) by the block on the spring and (b) by the spring on the block? (c) what is the value of h0? (d) if the block were released from height 2h0 above the spring, what would be the maximum compression of the spring?
Physics
1 answer:
galben [10]3 years ago
5 0
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs. 
Read more on Brainly.com - brainly.com/question/1581851#readmore
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How does area affect the pressure?​
dybincka [34]

The smaller the area the greater the pressure, while the bigger the smaller the pressure. So they are inversely proportional

5 0
3 years ago
A moonshiner makes the error of filling a glass jar to the brim and capping it tightly. The moonshine expands more than the glas
ohaa [14]

Answer:

ΔP = (640 N/cm^2)

Explanation:

Given:-

- The volume increase, ΔV/V0 = 4 ✕ 10^-3

- The Bulk Modulus, B = 1.6*10^9 N/m^2

Find:-

Calculate the force exerted by the moonshine per square centimeter

Solution:-

- The bulk modulus B of a material is dependent on change in pressure or Force per unit area and change in volume by the following relationship.

                                  B = ΔP / [(ΔV/V)]

- Now rearrange the above relation and solve for ΔP or force per unit area.

                                  ΔP = B* [(ΔV/V)]

- Plug in the values:

                                  ΔP = (1.6*10^9)*(4 ✕ 10^-3)

                                  ΔP = 6400000 N/m^2

- For unit conversion from N/m^2 to N/cm^2 we have:

                                  ΔP = (6400000 N/m^2) cm^2 / (100)^2 m^2

                                  ΔP = (640 N/cm^2)

7 0
3 years ago
When a falling meteoroid is at a distance above the earth's surface of 2.60 times the earth's radius, what is its acceleration d
Mice21 [21]

The gravitational acceleration at any distance r is given by

g=  \frac{GM}{r^2}

where G is the gravitational constant, M the Earth's mass and r is the distance measured from the center of the Earth.

The Earth's radius is r_e=6.37 \cdot 10^6 m, so the meteoroid is located at a distance of:

r=r_e+2.60 r_e =3.60 r_e =  2.29 \cdot 10^7 m

And by substituting this value into the previous formula, we can find the value of g at that altitude:

g=  \frac{GM}{r^2} =  \frac{(6.67 \cdot 10^{-11} m^3 kg^{-1} s^{-2})(5.97 \cdot 10^{24} kg)}{(2.29 \cdot 10^7 m)^2} =0.75 m/s^2

5 0
3 years ago
Read 2 more answers
When a pair of balanced forces acts on an object, the net force that results is.
polet [3.4K]
D.  Equal to zero.

Because the forces balance each other.
7 0
3 years ago
Consider two carts, of masses m and 2m, at rest on an air track. if you first push one cart for 3 s and then the other for the s
Marrrta [24]
F = m₁ a₁ = m₂ a₂

if m₁ = m and m₂ = 2m :

F = ma₁ = 2m  a₂ ⇒ a₁ = 2 a₂
 
since v = at + v₀  with t = 3, v₀ = 0 ⇒ v = 3a:

v₁ = 2 v₂

since p = vm with v₁ = 2v and v₂ = v :

p₁ = v₁m₁ = 2v ⁻ m
p₂ = v₂m₂ = v ⁻ 2m

p₁ = p₂

8 0
3 years ago
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