Answer:
a. the work done by the gravitational force on Block A is <u>less than</u> the work done by the gravitational force on Block B.
b. the speed of Block A is <u>equal to</u> the speed of Block B.
c. the momentum of Block A is <u>less than</u> the momentum of Block B.
Explanation:
a. The work done by the gravitational force is equal to:
w = m*g*h
where m is mass, g is the standard gravitational acceleration and h is height. Given that both blocks are released from rest at the same height, then, the bigger the mass, the bigger the work done.
b. With ramps frictionless, the final speed of the blocs is:
v = √(2*g*h)
which is independent of the mass of the blocks.
c. The momentum is calculated as follows:
momentum = m*v
Given that both bocks has the same speed, then, the bigger the mass, the bigger the momentum.
An ammeter should be connected in series with the resistor to measure the current through it. If it is connected in parallel, its low resistance would cause a short circuit.
A voltmeter should be connected in parallel with the resistor to measure the voltage across it. If connected in series, its high resistance would cause no current to flow and thus it would show a very small or no reading.
B.
increases as the tension of the string increases
Momentum = (mass) x (velocity)
Original momentum before the hit =
(0.16 kg) x (38 m/s) this way <==
= 6.08 kg-m/s this way <==
Momentum after the hit =
(0.16) x (44 m/s) that way ==>
= 7.04 kg-m/s that way ==>
Change in momentum = (6.08 + 7.04) = 13.12 kg-m/s that way ==> .
-----------------------------------------------
Change in momentum = impulse.
Impulse = (force) x (time the force lasted)
13.12 kg-m/s = (force) x (0.002 sec)
(13.12 kg-m/s) / (0.002 sec) = Force
6,560 kg-m/s² = 6,560 Newtons = Force
( about 1,475 pounds ! ! ! )