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2 years ago

What force is needed to move a 5 kg mass with an acceleration of 5 m/s²?

Physics

2 answers:

ElenaW [278]2 years ago

4 0

Answer:

b)25N

Explanation:

F=ma

F=(5kg)(5m/s^2)

F=25N

saw5 [17]2 years ago

3 0

Answer:

B 25

Explanation:

here's a very easy way looking at the question just do 5 x 5 or 5 kg x 5 m/s^2

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When water freezes, its volume increases by 9.05% (that is, equation). What force per unit area is water capable of exerting on

PIT_PIT [208]

Answer:

1.991 × 10^(8) N/m²

Explanation:

We are told that its volume increases by 9.05%.

Thus; (ΔV/V_o) = 9.05% = 0.0905

To find the force per unit area which is also pressure, we will use bulk modulus formula;

B = Δp(V_o/ΔV)

Making Δp the subject gives;

Δp = B(ΔV/V_o)

Now, B is bulk modulus of water with a value of 2.2 × 10^(9) N/m²

Thus;

Δp = 2.2 × 10^(9)[0.0905]

Δp = 1.991 × 10^(8) N/m²

3 0

3 years ago

As shown above an adhesive has been applied to contacting faces of two blocks so that the blocks interact with an adhesive force

rusak2 [61]

The magnitude of the adhesive force allows the top block to remain

attached to the bottom when the blocks and the wire are balanced.

The option that must be true is; $\mathbf{W_{bottom} = F_{adhesion}}$

Reason:

The tension exerted by the wire attached to the top block = T

Magnitude of the adhesive = $F_{adhesion}$

Weight of the top block = $W_{top}$

Weight of the bottom block = $W_{bottom}$

Given that with the exertion of the tension, the two blocks remain at rest, we have;

T = $W_{top}$ + $W_{bottom}$

The adhesive causes the bottom block to remain attached to the top block, we have;

Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;

The magnitude of the adhesive force = The weight of the bottom block

Therefore;

$W_{bottom}$ = $F_{adhesion}$

Learn more here:

brainly.com/question/18907970

8 0

3 years ago

Calculate the minimum thickness (in nm) of an oil slick on water that appears blue when illuminated by white light perpendicular

mr_godi [17]

Answer:

The minimum thickness = 83.92 nm

Explanation:

The relation between the wavelength in a particular medium and refractive index $\lambda_n = \frac{ \lambda }{n}$

where ;

$\lambda$ = wavelength of the light in vacuum

n = refractive index of medium with respect to vacuum

For one phase change :

$2t = \frac{\lambda_n}{2}\\\\where \ \lambda_n = \frac{\lambda}{n}\\\\Then \ \\\\2t = \frac{\lambda}{2n}\\\\t = \frac{\lambda_n}{4n}$

Replacing 1.43 for n and 480 nm for λ; we have:

$t = \frac{480}{4(1.43)}$

t = 83.92 nm

Thus; the minimum thickness = 83.92 nm

4 0

3 years ago

Are Carbon and oxygen are both metalloids?

Marizza181 [45]

Just carbon is a metalloid not oxygen

7 0

3 years ago

A pendulum takes 6.0 seconds to swing through 5 complete cycles. What is the period of the pendulum?

photoshop1234 [79]

When you look at this, you might not be sure which way to divide ...
Should you divide 6 by 5 or 5 by 6 ?

Here's a case where you can use your units to decide.

The question wants to know the 'period'. That's a length of time,
so the answer needs to have units of time.

If you divide 'cycles' be 'time', you'll get 'cycles/second'.
That's Hz. It's frequency, not time.

If you divide 'time' by 'cycles', you'll get 'seconds/cycle'.
That's time, and it's exactly the definition of 'period'.

Period = (6 seconds) / (5 cycles)

= (6 / 5) seconds/cycle

= 1.2 seconds

6 0

3 years ago