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Mademuasel [1]
3 years ago
11

During a total lunar eclipse, the moon

Physics
2 answers:
Anit [1.1K]3 years ago
8 0

A,  C,  and  D  all happen at different stages
of a total lunar eclipse.

I'll describe the stages of the eclipse, but before I do, I just need
to clarify:  The Earth doesn't have an umbra or a penumbra, but
its shadow does.
 

-- the eclipse begins when the first edge of the moon
   moves into the penumbra of Earth's shadow; ( C )
   this part of the moon grows steadily.

-- After a while, the first edge of the moon begins to move
   into the umbra of Earth's shadow ( A ), and gets very dark.

-- The total phase of the eclipse begins when the ENTIRE
    moon is in the umbra of Earth's shadow.

Then everything happens in reverse.

--  Eventually, the leading edge of the moon moves out
     of the shadow's umbra, into the penumbra.  This part
     steadily grows.  

-- After a while, none of the moon is in the umbra, and
   the whole thing is in the penumbra.  The moon is
   fully illuminated, but not quite as bright as it should be.

--  Soon, the leading edge of the moon leaves the penumbra
    of Earth's shadow, and gets brighter.  This portion of the moon
    steadily grows, until ...

--  the moon completely leaves the penumbra, all of it is as bright
    as it's supposed to be.  The eclipse is completely over.  ( B )


==>  The whole process lasts several hours.

==>  Everybody on the night side of the Earth sees the same thing
         at the same time.  It doesn't matter WHERE you are on the night
         side ... if you can see the moon in the sky, you see the present
         phase of the eclipse.

==>  The lunar eclipse can only happen at the Full Moon.  In fact, the
         mid-point of the total phase is the exact moment of Full Moon.

lidiya [134]3 years ago
5 0
The answer would be A) Moves into Earth's umbra. Hope this helps!!
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Calculate the minimum frequency of ultrasound (in Hz) that will allow you to see details as small as 0.193 mm in human tissue. (
STatiana [176]

Answer:

f = 7.97 x 10⁶ Hz = 7.97 MHz

Explanation:

The speed of a wave is given by the following formula:

v = f\lambda

where,

v = speed of the ultrasound wave through human tissue = 1540 m/s

f = frequency of ultrasound wave required = ?

λ = wavelength of ultrasound waves = smallest detail required = 0.193 mm

λ = 0.193 mm = 1.93 x 10⁻⁴ m

Therefore,

1540\ m/s = f(1.93\ x\ 10^{-4}\ m)\\f = \frac{1540\ m/s}{1.93\ x\ 10^{-4}\ m}

<u>f = 7.97 x 10⁶ Hz = 7.97 MHz</u>

8 0
3 years ago
In a nuclear fusion reaction two 2H atoms are combined to produce one 4He.
Mrrafil [7]

Answer:

a)= 0.025602u

b) = 23.848MeV

c) N = 1.546 × 10¹³

Explanation:

The reaction is

²₁H   +   ²₁H   ⇄   ⁴₂H + Q

a) The mass difference is

Δm = 2m(²₁H) - m (⁴₂H)

       = 2(2.014102u) - 4.002602u

        = 0.025602u

b) Use the Einstein mass energy relation ship

The enegy  release is the mass difference times 931.5MeV/U

E = (0.025602) (931.5)

   = 23.848MeV

c)

the number of reaction need per seconds is

N = Q/E

     = 59W/ 23.848MeV

  = \frac{59}{(23.848 \times 10^6 )(1.6 \times 10^1^9) } \\\\= 1.546 \times 10^1^3

N = 1.546 × 10¹³

5 0
3 years ago
What is my purpose?
castortr0y [4]
As Rene Descartes - french mathematician of Cartesian graphs - said "Cogito ergo sum". I think, therefore I am. 
This can be adapted to I think therefore I am, I think ... as a "geeky joke".
8 0
3 years ago
How many protons are in this atom if it has a balanced charge? 0 2 4 6
pickupchik [31]

Answer:

For an atom to have a balanced charged, the number of protons shall be equal to the number of electrons of an atom. proton is the positive part of an atom whereas electrons are the negative part of an atom. Only if the number of protons will be equal to the number of electron, the atom will be able to be neutral.

If the number of electron will be more, then the atom will be negative. If the number of electron will be less, then the atom will be positive.

7 0
3 years ago
Read 2 more answers
Blocks A and B are identical metal blocks. Initially block A is neutral, and block B has a net charge of 7.0 nC. Using insulatin
maxonik [38]

Answer:

Block A will have a final charge of 3.5nC.

Explanation:

This is because at the point of contact with Block B, which is electrically positive, the electrons in Block A will be attracted to the excess 'unpaired' protons in block B. Hence, the electrons will flow into Block B causing unpaired protons to remain in Block A.

This process is called Charging by Conduction.

This charging process will continue until the charges are evenly distributed between both objects.

In case you're wondering, "<em>how's all this possible within a few seconds</em>?", remember that electrons travel very fast and so, this process is a rather rapid one.

6 0
3 years ago
Read 2 more answers
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