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a_sh-v [17]
3 years ago
15

The surnames of 40 children in a class arranged in alphabetical order. 16 of the surnames begins with O and 9 of the surname beg

ins with A, 14, of the letters of the alphabet do not appear as the first letter of a surname If more than one surname begins with a letter besides A and O, how may surnames begin with that letter?
Mathematics
2 answers:
Damm [24]3 years ago
3 0

Step-by-step explanation:

40children - 23 (with A, O) = 17left

26 letter in alphabet- ( A, O) = 24 letter left

24 letters left - 14 (not used for 1st letters) = 10

10 letters left to use/ 17 children left

10÷17 = 0.5882352941 x 10 =5.8 or as close to 6 I can get

mixas84 [53]3 years ago
3 0

Answer:

14 of the letters of the alphabet do not appear as the first letter of surname

∴ the no. of letters that appeared = 26-14 = 12 alphabets

15 surnames begin with 10 letters beside O and A

∴ 6 surnames begin with a letter

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Does anyone have the answers for all?
Shkiper50 [21]

Answer and Step-by-step explanation:

1-6

a.

What you can do is plug in 6 and start by doing the first machine first, then the second. If this doesn't work, do the second machine, then the first machine.

<em><u>The order that works is second machine, then first machine.</u></em>

<u>Second Machine:</u>

y = (6)^{2} -6 = 36 - 6 = 30

Plug into first machine now.

<u>First Machine:</u>

y = \sqrt{(30) - 5}  = \sqrt{25} = 5

We see that the result is 5.

b. <em><u>If we were to do the order of second machine, then first machine, we will never get a negative result (or -5 for that matter), due to the fact that you can't algebraically square root a negative number.</u></em>

<em><u>However, if we were to do the order of first machine, second machine, we can get a negative number. To get -5, we plug in 6 for x in the first machine, getting an answer of 1. We plug this into the second machine, getting 1^2 - 6, which results in -5.</u></em>

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c. |3| - |-1| = 3 - 1 = <em><u>2</u></em>

d. |2.2 - 5.13| = |-2.93| = <em><u>2.93</u></em>

1-8.

a.

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u>

<u>|  ||  ||  ||  ||  |</u>

<u>(5 boxes on each side)</u>

_

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u>

<u>|  |</u> <u>  </u> <u>   </u> <u>  </u> <u>   </u> <u>   </u>

<u>|  ||  ||  ||  ||  ||  |</u>

<u>(6 boxes on each side)</u>

b.<em><u> The amount of squares on each side of the figure increases by 1.</u></em>

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i. \sqrt{49} = <em><u>7</u></em>

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<em><u>#teamtrees #PAW (Plant And Water)</u></em>

<em><u>I hope this helps!</u></em>

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