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a_sh-v [17]
3 years ago
15

The surnames of 40 children in a class arranged in alphabetical order. 16 of the surnames begins with O and 9 of the surname beg

ins with A, 14, of the letters of the alphabet do not appear as the first letter of a surname If more than one surname begins with a letter besides A and O, how may surnames begin with that letter?
Mathematics
2 answers:
Damm [24]3 years ago
3 0

Step-by-step explanation:

40children - 23 (with A, O) = 17left

26 letter in alphabet- ( A, O) = 24 letter left

24 letters left - 14 (not used for 1st letters) = 10

10 letters left to use/ 17 children left

10÷17 = 0.5882352941 x 10 =5.8 or as close to 6 I can get

mixas84 [53]3 years ago
3 0

Answer:

14 of the letters of the alphabet do not appear as the first letter of surname

∴ the no. of letters that appeared = 26-14 = 12 alphabets

15 surnames begin with 10 letters beside O and A

∴ 6 surnames begin with a letter

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The correct answer is:  3)  " x ;  1/2" .
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Explanation:
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Question 1) 

g [ f(x) ] = ? ;

→ Given:  " f(x) = 1/3 x " ;

→ Given:  " g(x) = 3x " ;  
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g [ f(x) ] = g(1/3 x) = 3(1/3 x) = 1x = "x" .
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Question 2)

g [ f(1/2) ] = ? ; 
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→  Given:  " f(x) = 1/3 x " ;

→  f(1/2) = (1/3) * (1/2) = (1*1) / (3*2) = (1/6) ;

→  g [ f(x) ] =  

          g(1/6) = 3* (1/6) = (3/1) * (1/6) = (3*1) / (1*6) = 3/6 = (3÷3) / (6÷3) = " 1/2 "  .
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