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2 years ago

As more bulbs are connected in series in a circuit, what happens to the brightness with which each glows?

Chemistry

2 answers:

madam [21]2 years ago

8 0

They dim unless more volts are added (batteries")

stepan [7]2 years ago

6 0

The luminosity decreases as more bulbs are added since the energy has to be divided between more bulbs

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Which of the following elements is a metalloid

klemol [59]

A metalloid can be:
- Boron (B)
- Silicon (Si)
- Germanium ( Ge)
- Arsenic (As)
- Antimony ( Sb)
- Tellurium (Te)
- Polonium (Po)

Hope this helps :)

6 0

3 years ago

Read 2 more answers

What are the cations and anions whose compounds are usually soluble?

HACTEHA [7]

Answer: -

Solubility of a substance depend on the balance of intermolecular forces between the solvent and solute, and the entropy change that accompanies this process.

Temperature and pressure also plays a role in solubility.

A solution having Group 1 cations like lithium, sodium, potassium etc are always soluble.

A solution having NH₄⁺ is soluble.

All salts with anion as nitrates, acetates, chlorates, and perchlorates are soluble in water.

8 0

2 years ago

What is pseudoscience?how is it different from non-science?

Anika [276]

Answer:

Pseudoscience is statements claiming to be backed by science, however don’t conform to the scientific method or present facts (most commonly are misconceptions). Whereas, non-science is the of non-scientific subjects, such as; art, history and religion.

Explanation:

5 0

2 years ago

Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a tank

Masja [62]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration equilibrium constant is $K_c = 14.39$

Explanation:

The chemical equation for this decomposition of ammonia is

$2 NH_3$ ↔ $N_2 + 3 H_2$

The initial concentration of ammonia is mathematically represented a

$[NH_3] = \frac{n_1}{V_1} = \frac{29}{75}$

$[NH_3] = 0.387 \ M$

The initial concentration of nitrogen gas is mathematically represented a

$[N_2] = \frac{n_2}{V_2}$

$[N_2] = 0.173 \ M$

So looking at the equation

Initially (Before reaction)

$NH_3 = 0.387 \ M$

$N_2 = 0 \ M$

$H_2 = 0 \ M$

During reaction(this is gotten from the reaction equation )

$NH_3 = -2 x$ (this implies that it losses two moles of concentration )

$N_2 = + x$ (this implies that it gains 1 moles)

$H_2 = +3 x$ (this implies that it gains 3 moles)

Note : x denotes concentration

At equilibrium

$NH_3 = 0.387 -2x$

$N_2 = x$

$H_2 = 3 x$

Now since

$[NH_3] = 0.387 \ M$

$x= 0.387 \ M$

$H_2 = 3 * 0.173$

$H_2 = 0.519 \ M$

$NH_3 = 0.387 -2(0.173)$

$NH_3 = 0.041 \ M$

Now the equilibrium constant is

$K_c = \frac{[N_2][H_2]^3}{[NH_3]^2}$

substituting values

$K_c = \frac{(0.173) (0.519)^3}{(0.041)^2}$

$K_c = 14.39$

3 0

2 years ago

Why does air have different pressures

yaroslaw [1]

Because, at lower elevation, everything is tightly packed, and theres more air. As for at higher elevation (like for example at the top of mount everest) There is less air... The higher the elevation, the less air.
<em>~Hope this helped! :)</em>

6 0

2 years ago