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alukav5142 [94]
3 years ago
13

What is the element with the lowest electronegativity value? A. Cesium B. Helium C. Calcium D. Fluorine

Chemistry
1 answer:
Anna007 [38]3 years ago
7 0
A.) Cesium is the lowest electronegative element......
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a rock is examined to determine its age, and the ratio of uranium-235 to lead-207 is found to be 125,000:875,000. the half-life
slamgirl [31]

The old age of rock when examined is 21.4 million years if the ratio of uranium-235 to lead-207 is found to be 125,000:875,000. the half-life of uranium-235 is 700 million years.

<h3>Decaying Equation </h3>

P = [P + D] (1/2) ^(t/t(1/2))

where,

P represent the present parent amount

D is the present daughter amount

t(1/2) is the half life time period

t is the actual age

We know that,

t = (log[(P+D) /P] / log2) × t(1/2) ----------(1)

Given,

P = 97.6

D = 2.1

Ratio of P and D can be calculated as

P/D = 97.6/2.1

= 46.476

By substituting all the values in eq(1), we get

t = [(log 46.476 +1)/log2] × t(1/2)

Given,

The half life of U —Pb decay is 700 million years.

So,

t = [(log 46.476 +1)/log2] × 700

t = 21.4 million years.

Thus, we calculated that the the old age of rock when examined is 21.4 million years.

learn more about Half life period:

brainly.com/question/20309144

#SPJ4

DISCLAIMER:

The given question is misprint on portal.

Here is the correct form of question:

A rock is examined to determine its age, and the ratio of uranium-235 to lead-207 is found to be 125,000:875,000. the half-life of uranium-235 is 700 million years.

How old is the rock if it contains Uranium-235/ lead-207 ratio of 97.6 to 2.1?

8 0
2 years ago
What occurs in photosynthesis reaction
marusya05 [52]

Answer and Explanation:

Photosynthesis reaction involves two reactants, carbon dioxide and water. These two reactants yield two products, namely, oxygen and glucose.

6 0
3 years ago
What are 4 other gases in the atmosphere besides oxegen and nitergin?
Levart [38]
Helium, neon,nitrogen and argon
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Predict the products of the reaction below. that is, complete the right-hand side of the chemical equation. be sure your equatio
kkurt [141]
The equation is as follow,

<span>                                  HBr </span>₍aq₎  +  H₂O ₍l₎    →

Solution:
             HBr being strong acid with Ka value of 1.0 × 10⁹. When HBr is added to water, water acts as a base and HBr acts as a acid. Water picks the proton (H⁺) from HBr and converts into Conjugate acid (H₃O⁺) ahile HBr is converted into Conjugate Base (Br⁻) after loosing proton. The equation for this reaction is as follow,

                      HBr ₍aq₎  +  H₂O ₍l₎    →    H₃O⁺ ₍aq₎  +  Br⁻ ₍aq₎
8 0
4 years ago
The formula of nitrogen oxide is NO, of nitrogen dioxide is NO_2. Write a balanced equation for the reaction of nitrogen oxide w
denis23 [38]

Answer:

a) 0,5 mol O₂; 1 mol NO₂

b)

Liters of NO = 22,4 L

Liters of O₂ = 11,2 L

Liters of NO₂ = 22,4 L

c) NO = 30g

O₂ = 16g

NO₂ = 46g

d) 7,41g HCl

e) 107,7 g/mol

f) 0,0312 moles of O₂; 0,999g of O₂; 699 mL at STP or 803 mL

ii. 51%

g) 32,6L

Explanation:

a) For the reaction:

2 NO + O₂ → 2 NO₂

For 1 mole of NO there are consumed:

1 mol NO ×\frac{1molO_{2}}{2molNO} = <em>0,5 mol of O₂</em>

And produced:

1 mol NO ×\frac{2molNO_{2}}{2molNO} = <em>1 mol of NO₂</em>

b) By ideal gas law:

V = nRT/P

Where n is moles of each compound; R is gas constant (0,082atmL/molK); T is temperature (273,15 K at state conditions); P is pressure (1 atm at STP) and V is volume in liters. Replacing each moles for each compound:

Liters of NO = 22,4 L

Liters of O₂ = 11,2 L

Liters of NO₂ = 22,4 L

c) The mass of each compound are:

1 mol NO×\frac{30 g}{1molNO} = <em>30g</em>

0,5 mol O₂×\frac{32 g}{1molO_{2}} = <em>16g</em>

1 mol NO₂×\frac{46 g}{1molNO_{2}} = <em>46g</em>

d) Using:

n = PV / RT

Moles of 4,55 L of HCl (using the values of P = 1 atm; R = 0,082atmL/molK; T = 273,15K) are:

0,203 moles of HCl. In grams:

0,203 mol HCl×\frac{36,46 g}{1molHCl} = <em>7,41 g of HCl</em>

e) Using:

δRT/P = MW

Where δ is density in g/L (4,81 g/L); R is gas constant (0,082atmL/molK); T is temperature (273,15K); P is pressure (1 atm)

And MW is molecular mass: <em>107,7 g/mol</em>

f) For the reaction:

2 KClO₃ → 2 KCl + 3 O₂

2,550 g of KClO₃ are:

2,550 g of KClO₃×\frac{1mol}{122,55 gKClO_{3}} = 0,0208 moles of KClO₃

When these moles reacts completely produce:

0,0208 moles of KClO₃×\frac{3 mol O_{2}}{2 molKClO_{3}} = <em>0,0312 moles of O₂</em>

In grams:

0,0312 moles of O₂ ×\frac{32g}{1 molO_{2}} = <em>0,999g of O₂</em>

V = nRT/P

At STP, n = 0,0312 mol; R = 0,082atmL/molK;T= 273,15K; P = 1atm; <em>V = 0,699L ≡ 699mL</em>

At 29 °C (302,15K) and 732 torr (0,963 atm)

<em>V = 0,803L ≡ 803mL</em>

ii. 182 mL ≡ 0,182L of O₂ are:

n = PV/RT

moles of O₂ are 7,07x10⁻³. Moles of KClO₃ are:

7,07x10⁻³ moles of O₂×\frac{2 mol KClO_{3}}{3 molO_{2}} = 0,0106 mol KClO₃. In grams:

0,0106 moles of KClO₃×\frac{122,55 g}{1molKClO_{3}} = 1,300 g of KClO₃.

Thus, percent by mass of KClO₃ in the mixture is:

1,300g/2,550g ×100 = <em>51%</em>

g. Combined gas law says that:

\frac{P_{1}V_{1}}{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

Where:

P₁ = 755 torr; V₁ = 35,9L; T₁ = 26°C (299,15 K); P₂ = 760 torr (STP): T₂ = 273,15K (STP) <em>V₂ = 32,6 L</em>

<em></em>

I hope it helps!

4 0
3 years ago
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