POH will be -log[conc of OH]
-log (3.9E-08) = 7.409
pH = 14- pOH
pH = 14 - 7.409
pH = 6.59
2 H₂O₂ --> 2 H₂ + 2 O₂
2 moles H₂O₂ ------> 2 moles O₂
8 moles H₂O₂ ------> ?
moles O₂ = 8 x 2 / 2
moles O₂ = 16 / 2
= 8 moles
Answer C
hope this helps!
D
because they are elements in the same group as strontium
Answer:

Explanation:
Hello,
In this case, the reaction between sulfuric acid and hydroxide is:

We can notice a 1:2 molar ratio between the acid and the base respectively, therefore, at the equivalence point we have:

And in terms of volumes and concentrations:

So we compute the molarity of sulfuric acid as shown below:

Best regards.