Question

an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the device

Answer 1

Answer: R=24.2Ω

Explanation: Power is rate of work being done in an electric circuit. It relates to voltage, current and resistance through the following formulas:

P=V.i

P=R.i²

$P=\frac{V^{2}}{R}$

The resistance of the system is:

$P=\frac{V^{2}}{R}$

$R=\frac{V^{2}}{P}$

$R=\frac{110^{2}}{500}$

R = 24.2Ω

For the device, resistance is 24.2Ω.