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3 years ago

Scattered. The particles. are not

1 answer:

5 0

the change in the direction of motion of a particle because of a collision with another particle. As defined in physics, a collision can occur between particles that repel one another, such as two positive (or negative) ions, and need not involve direct physical contact of the particles

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I need some help with crush advise. So basically i have a crush on this dude but i don't think he know me we are not in the same

Maru [420]

Answer:

Go for it!

Explanation:

You only live once, seriously just go up and talk to him. Say something like, "Hey, you seemed cool I just wanted to say hi. Do you have an ig?" :) you won't regret it.

8 0

1 year ago

Read 2 more answers

Enter your answer in the provided box.S(rhombic) + O2(g) → SO2(g) ΔHo rxn= −296.06 kJ/molS(monoclinic) + O2(g) → SO2(g) ΔHo rxn=

IgorC [24]

Answer: $\Delta H^0=+0.3kJ/mol$ .

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

$S_{rhombic}+O_2(g)\rightarrow SO_2(g)$ $\Delta H^0_1=-296.06kJ$ (1)

$S_{monoclinic}+O_2(g)\rightarrow SO_2(g)/tex] [tex]\Delta H^0_2=-296.36kJ$ (2)

The final reaction is:

$S_{rhombic}\rightarrow S_{monoclinic}$ $\Delta H^0_3=?$ (3)

By subtracting (1) and (2)

$\Delta H^0_3=\Delta H^0_1-\Delta H^0_2=-296.06kJ-(-296.36kJ)=0.3kJ$

Hence the enthalpy change for the transformation S(rhombic) → S(monoclinic) is 0.3kJ

3 0

3 years ago

Question 26 Suppose a flask is filled with of and of . The following reaction becomes possible: The equilibrium constant for thi

Blizzard [7]

Answer:

0.36 M

Explanation:

There is some info missing. I think this is the complete question.

Suppose a 250 mL flask is filled with 0.30 mol of N₂ and 0.70 mol of NO. The following reaction becomes possible:

N₂(g) +O₂(g) ⇄ 2 NO(g)

The equilibrium constant K for this reaction is 7.70 at the temperature of the flask. Calculate the equilibrium molarity of O₂. Round your answer to two decimal places.

Initially, there is no O₂, so the reaction can only proceed to the left to attain equilibrium. The initial concentrations of the other substances are:

[N₂] = 0.30 mol / 0.250 L = 1.2 M

[NO] = 0.70 mol / 0.250 L = 2.8 M

We can find the concentrations at equilibrium using an ICE Chart. We recognize 3 stages (Initial, Change, and Equilibrium) and complete each row with the concentration or change in the concentration.

N₂(g) +O₂(g) ⇄ 2 NO(g)

I 1.2 0 2.8

C +x +x -2x

E 1.2+x x 2.8 - 2x

The equilibrium constant (K) is:

$K=7.70=\frac{[NO]^{2}}{[N_{2}][O_{2}]} =\frac{(2.8-2x)^{2} }{(1.2+x).x}$

Solving for x, the positive one is x = 0.3601 M

[O₂] = 0.3601 M ≈ 0.36 M

7 0

3 years ago

What is kinetix energy

posledela

Answer:

Kinetic energy is the energy developed in a body due to of its motion.It is denoted by KE

and given by,KE=

$\frac{1}{2} m {v}^{2}$

It's SI unit is J.

5 0

3 years ago

1. Explain what is in a buffer. Discuss the function of a buffer. How will pH change when small amounts of acids or bases are ad

Nastasia [14]

Answer:

(1) See below, (2) About 8.4 pH, (3) About 3.981 * 10⁻⁶ mol dm⁻³

Explanation:

1. A buffer is a solution that resist pH when adding a basic or acidic compound. It's purpose is to neutralize added acids and bases.

2. Remember that the formula for pH is -log [H+]. We have a 0.1 M solution of baking soda in water with [H+] of about 4.0 × 10⁻⁹. Therefore we can calculate the pH as follows...

pH = -log (4.0 × 10⁻⁹)

pH = -(-8.39794...) = (About) 8.4 pH of 0.1 M of baking soda

3. This question has a similar set up...

pH = -log [H+]

[H+] = inverse of log^- pH

[H+] = 10^-5.4 = (About) 3.981 $*$ 10⁻⁶

4 0

3 years ago