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4 years ago

14

Suitably qualified individuals who write prescriptions for controlled substances are assigned a number which contains two letter

s and seven digits. This number is the A. physicians practice number. B. prescriber's license code. C. DEA number. D. CDC number.

1 answer:

daser333 [38]4 years ago

8 0

B. Prescriber’s license code

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An object initially at rest experiences an acceleration of 9.8m/s2. How much time will it take it to achieve a velocity of 49m/s

Vlad1618 [11]

Answer:5seconds

Explanation:

initial velocity(u)=0

Final velocity(v)=49m/s

acceleration(a)=9.8m/s2

Time(t)=?

V=u+axt

49=0+9.8xt

49=9.8t

t=49/9.8

t=5seconds

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4 years ago

Comparing the speed of sound in liquids, gases, and solids, the speed of sound is usually lowest in ( ) and highest in ( ).

nydimaria [60]

Answer:

the answer is the 4th one. the speed of sound is lowest in gas and highest in solid and its because the molecules in solid is closer to each other than the molecules in gas and when the molecules are close to each other, they allow the waves of the sound to travel more quickly.

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3 years ago

Approximately how much of Earth’s water is freshwater?

marishachu [46]

50% water is fresh into Earth

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4 years ago

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When you have been swimming swimming and you come out of the pool, you may feel cold. Use your understanding of endothermic proc

Leona [35]

Explanation:

Edothermic process is the absorbtion of heat.

It is the opposite of exothermic process which is the release of energy. In edothermic process thermal energy is absorbed from the surrounding

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3 years ago

Two point charges exert a 7.35 N force on each other. What will the force become if the distance between them is increased by a

I am Lyosha [343]

Answer :

New force becomes, F' = 1.83 N

Explanation:

Let two point charges exert a force of 7.35 N force on each other. The electric force between two charges is given by :

$F=\dfrac{kq_1q_2}{r^2}$

$q_1\ and\ q_2$ are charges

r is the distance between charges if the distance between them is increased by a factor of 2, r' = 2r

New force is given by :

$F'=\dfrac{kq^2}{r'^2}$

$F'=\dfrac{kq^2}{(2r)^2}$

$F'=\dfrac{1}{4}\dfrac{kq^2}{r^2}$

$F'=\dfrac{1}{4}\times 7.35$

F' = 1.83 N

So, the new force between charges will be 1.83 N. Therefore, this is the required solution.

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3 years ago