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timurjin [86]
3 years ago
14

Bob and Lily are riding on a typical carousel. Bob rides on a horse near the outer edge of the circular platform, and Lily rides

on a horse near the center of the circular platform. When the carousel is rotating at a constant angular speed, Bob's angular speed is
Physics
1 answer:
alukav5142 [94]3 years ago
6 0

Answer:

Bob's angular speed is the same as that of lily

Explanation:

Because for a carousel the angular speed remains the same since velocity at center and edge are the same

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A fox fleeing from a hunter encounters a 0.700 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.
iris [78.8K]

Answer:0.61 m

Explanation:

Given

Initial velocity (u)=7.40 m/s

launch angle \theta =45^{\circ}

height of fence=0.7 m

Trajectory of Projectile is given by

y=x\tan \theta -\frac{gx^2}{2u^2\cos^2\theta }

For x=2.1 m  

y=2.1\tan (45)-\frac{9.8\times 2.1^2}{2\times 7.4^2\times (\cos 45)^2}

y=2.1-0.789

y=1.31 m

At x=2.1 m Y=1.31

therefore Fox clear fence by a margin =1.31-0.7=0.61 m

7 0
3 years ago
A B-52 bomber jet flies at a horizontal velocity of 286.2 m/s and at an altitude of 7500 m above the ground.
kykrilka [37]

Answer:

you need to divide 7500/286.2

3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Nostrana [21]

Don't look now, but the question GIVES you the formula to use, and it GIVES you the numbers to plug into the formula.

The formula to use to find the distance covered by the sound is

<em>Speed = (distance) / (time)</em>

They also give you:

speed = 330 m/s

time = 0.40 second

Stuff the numbers into the formula:

330 m/s = (Distance) / (0.40 second)

Multiply each side by (0.40 second), and you get:

(330 m/s) / (0.4 second) = Distance

<em>825 meters = Distance</em>

4 0
3 years ago
Read 2 more answers
What is the specific definition of energy that relates it to work?
Crazy boy [7]
A b c d e f g h i j k l m
5 0
3 years ago
A particular spring has a spring constant of 25 N/m.
kotegsom [21]

Answer:

<h2>2.8×10^-3</h2>

e.p.e =  \frac{1}{2} k {x}^{2}   \\   = \frac{1}{2}  \times 25 \times (0.015m)^{2}  \\  = 0.0028125

<u>0.0028125N</u><u> </u>

8 0
3 years ago
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