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The frequency f of a wave is defined as the inverse of the period T:
The clock in the problem has a waveform with period
. Therefore, its frequency is
The clock in the problem has a waveform with period
Answer:
the diameter of the outside edge of the receiver is
Explanation:
From the schematic free body diagram illustrating what the question is all about below;
Let represent A to be the vertex where the receiver is being placed
S to be the focus
BP to be equal to r (i.e radius of the outer edge)
BC to be 2 r (i.e the diameter)
Given that AS = 4 in and AP is 18 in
Let AP be x- axis and AY be y -axis
A=(0,0)
S=(4,0) = (0,0)
So that the equation of the parabolic path of the receiver will be:
B = (AP, BP)
B = (18, r)
B lies y² = 16 x
r² = 16 x
r² 16 × 18
Diameter BC = 2r
