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2 years ago

A body of mass 10kg has a height of 200cm, calculate the potential energy. (Take g =

Physics

2 answers:

zaharov [31]2 years ago

6 0

Explanation:

$potential \: energy = mgh \\ m = 10kg \\ g = 10 \frac{m}{s} \\ h = 200cm = 2m \\ pe = 10 \times 10 \times 2 = 200joule \\ thank \: you$

Nastasia [14]2 years ago

5 0

The potential energy of the body is "200 Joule".

According to the question,

Mass,

m = 10 kg

Height,

h = 200 cm

or,

= 2 m

g = 10 m/s⁻¹

As we know,

→ The potential energy will be:

= $mgh$

By putting the given values, we get

= $10\times 10\times 2$

= $200 \ Joule$

Thus the above answer is right.

Learn more about potential energy here:

brainly.com/question/23859978

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Question 20 (4 points)

irinina [24]

Explanation:

C is correct.

Newton second law states that force is directly proportional to acceleration with m being the constant of variation.

$f _{net} = m(a)$

$250 = 50(a)$

$a = 5$

A is wrong, the constant g only happens in free fall or in vertical direction

B and D are wrong due to the mathematical error or equation error

3 0

2 years ago

Compare and contrast the way molecules behave in liquid to the way they behave in solids and gases.

Vitek1552 [10]

In liquids, molecules particles are close together but move in random directions.

In solids, they are closely packed together and they vibrate a little.

In gases, they love around really quickly and are farther apart (even more than liquids).

3 0

2 years ago

Read 2 more answers

Spitting cobras can defend themselves by squeezing muscles around their venom glands to squirt venom at an attacker. Suppose a s

Alenkasestr [34]

Answer: 1.289 m

Explanation:

The path the cobra's venom follows since it is spitted until it hits the ground, is described by a parabola. Hence, the equations for parabolic motion (which has two components) can be applied to solve this problem:

<u>x-component: </u>

$x=V_{o}cos\theta t$ (1)

Where:

$x$ is the horizontal distance traveled by the venom

$V_{o}=3.10 m/s$ is the venom's initial speed

$\theta=47\°$ is the angle

$t$ is the time since the venom is spitted until it hits the ground

<u>y-component: </u>

$y=y_{o}+V_{o}sin\theta t+\frac{gt^{2}}{2}$ (2)

Where:

$y_{o}=0.44 m$ is the initial height of the venom

$y=0$ is the final height of the venom (when it finally hits the ground)

$g=-9.8m/s^{2}$ is the acceleration due gravity

Let's begin with (2) to find the time it takes the complete path:

$0=0.44 m+3.10 m/s sin\theta(47\°)+\frac{-9.8m/s^{2} t^{2}}{2}$ (3)

Rewritting (3):

$-4.9 m/s^{2} t^{2} + 2.267 m/s t + 0.44 m=0$ (4)

This is a quadratic equation (also called equation of the second degree) of the form $at^{2}+bt+c=0$ , which can be solved with the following formula:

$t=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ (5)

Where:

$a=-4.9 m/s^{2$

$b=2.267 m/s$

$c=0.44 m$

Substituting the known values:

$t=\frac{-2.267 \pm \sqrt{2.267^{2}-4(-4.9)(0.44)}}{2(-4.9)}$ (6)

Solving (6) we find the positive result is:

$t=0.609 s$ (7)

Substituting (7) in (1):

$x=(3.10 m/s)cos(47\°)(0.609 s)$ (8)

We finally find the horizontal distance traveled by the venom:

$x=1.289 m$

7 0

3 years ago

What is the kinetic energy of a 2.7kg book

Tanya [424]

16.5375 .................

3 0

3 years ago

Consider the following neutral electron configurations in which n has a constant value. Which configuration would belong to the

grandymaker [24]

Answer:

he configuration with the highest electronic affinity is 2s2 2p5

Explanation:

Electronic affinity is the variation of energy when we add an electron to a neutral atom to form an ion

When an electron is added, it must occupy a space is the sub-level of the atom, giving more stability when it approaches the configuration of a complete shell with eight electrons (noble gas), so the affinity must increase when moving in a period Group VIII noble gases)

Let's examine the given settings

In this case, when adding an electron, 2s2 is very far from a complete level configuration, so its affinity must be small.

2s2 2p2 when adding an electro the one has a little more affinity, but is still a long way from a full shell, it would be missing 3 electrons

2s2 2sp5 this is the atom with the highest electronic affinity, since i = that when adding an electron the ion has the configuration of a noble gas. This is the most stable on the list

2s2 2p6 already has a full shell making it very difficult to insert an electron into this atom.

In summary, the configuration with the highest electronic affinity is 2s2 2p5

3 0

3 years ago

Read 2 more answers