1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Scorpion4ik [409]
2 years ago
6

Please select the word from the list that best fits the definition

Physics
2 answers:
vagabundo [1.1K]2 years ago
7 0

Answer:input work

Explanation:

Diano4ka-milaya [45]2 years ago
3 0

Answer:

thankssssssssss\

Explanation:

You might be interested in
an object is moving east with a constant speed of 20m/s for 4 seconds.What is the object's acceleration
Tamiku [17]

The objects acceleration is 6m/s.

5 0
2 years ago
Refer to the first diagram. What is the weight of the person hanging on the end of the seesaw in Newtons?
irina1246 [14]

Due to equilibrium of moments:

1) The weight of the person hanging on the left is 250 N

2) The 400 N person is 3 m from the fulcrum

3) The weight of the board is 200 N

Explanation:

1)

To solve the problem, we use the principle of equilibrium of moments.

In fact, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

The moment of a force is defined as:

M=Fd

where

F is the magnitude of the force

d is the perpendicular distance of the force from the fulcrum

In the first diagram:

- The clockwise moment is due to the person on the right is

M_c = W_2 d_2

where W_2 = 500 N is the weight of the person and d_2 = 2 m is its distance from the fulcrum

- The anticlockwise moment due to the person hanging on the left is

M_a = W_1 d_1

where W_1 is his weight and d_1 = 4 m is the distance from the fulcrum

Since the seesaw is in equilibrium,

M_c = M_a

So we can find the weight of the person on the left:

W_1 d_1 = W_2 d_2\\W_1 = \frac{W_2 d_2}{d_1}=\frac{(500)(2)}{4}=250 N

2)

Again, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

- The clockwise moment due to the person on the right is

M_c = W_2 d_2

where W_2 = 400 N is the weight of the person and d_2 is its distance from the fulcrum

- The anticlockwise moment due to the person on the left is

M_a = W_1 d_1

where W_1 = 300 N is his weight and d_1 = 4 m is the distance from the fulcrum.

Since the seesaw is in equilibrium,

M_c = M_a

So we can find the distance of the person on the right:

W_1 d_1 = W_2 d_2\\d_2 = \frac{W_1 d_1}{W_2}=\frac{(300)(4)}{400}=3 m

3)

As before, for the seesaw to be in equilibrium, the total clockwise moment must be equal to the total anticlockwise moment.

- The clockwise moment around the fulcrum this time is due to the weight of the seesaw:

M_c = W_2 d_2

where W_2 is the weight of the seesaw and d_2 = 3 m is the distance of its centre of mass from the fulcrum

- The anticlockwise moment due to the person on the left is

M_a = W_1 d_1

where W_1 = 600 N is his weight and d_1 = 1 m is the distance from the fulcrum

Since the seesaw is in equilibrium,

M_c = M_a

So we can find the weight of the seesaw:

W_1 d_1 = W_2 d_2\\W_2 =\frac{W_1 d_1}{d_2}= \frac{(600)(1)}{3}=200 N

#LearnwithBrainly

8 0
2 years ago
A truck is driving north at 35 miles per hour and passes a car going south at 40 miles per hour. What is the speed of the car fr
inna [77]

Answer:

70

Explanation:

right...

7 0
2 years ago
Read 2 more answers
Birds fly south for the winter.bats hibernate during winter.what are these examples of
Alecsey [184]
The animals need less food people it is winter time. 
6 0
3 years ago
Read 2 more answers
A train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity​
Kobotan [32]

Complete question:

A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity​ after 10s ?

Answer:

the final velocity of the train is 4 m/s.

Explanation:

Given;

initial velocity of the train, u = 44 m/s

acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)

time of motion, t = 10 s

let the final velocity of the train = v

The final velocity of the train is calculated using the following kinematic equation;

v = u + at

v = 44 + (-4 x 10)

v = 44 - 40

v = 4 m/s

Therefore, the final velocity of the train is 4 m/s.

7 0
3 years ago
Other questions:
  • uppose that 3 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 45 cm. (a) How much work i
    15·1 answer
  • An automobile tire is rated to last for 60,000 miles. to an order of magnitude, through how many revolutions will it turn?
    11·1 answer
  • Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter
    11·1 answer
  • Which property of a circuit is equal at every point on a parallel circuit?​
    13·1 answer
  • How much he is given out 185 g of lead cools from 200 Celsius to 10 Celsius
    10·1 answer
  • Cylinder A has a mass of 2kg and cylinder B has a mass of 10kg. Determinethe velocity of A after it has displaced 2m from its or
    11·1 answer
  • The diagram shows changes of state between solid, liquid, and gas. The atoms of a substance lose energy during a change of state
    7·2 answers
  • A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.60 m/s. The car is a distan
    7·1 answer
  • A firetruck drive 3 miles to the east and 1.2 miles to the west what is the displacement of the firetruck
    8·1 answer
  • A 5.00 kg crate is on a 21.0° hill.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!