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3 years ago

Is NO ionic or covalent

1 answer:

8 0

Covalent

A covalent bond is the bond where electrons are shared. This occurs between two non mental. N is nitrogen and O is oxygen, therefore NO would be a bond between two non metals. So it must be covalent.

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A reaction produces 10.5 L if oxygen, but was supposed to produce 1 mol of oxygen. What is the percent yield ? (One mole of any

Rzqust [24]

To answer this item, we assume that oxygen behaves ideally such that it is able to fulfill the following equation,

PV = nRT

If we are to retain constant the variable n and V.

The percent yield can therefore be solved through the following calculation,

n = (10.5 L)/(22.4 L) x 100%

Simplifying,
n = 46.875%

Answer: 48.87%

5 0

3 years ago

1. How are electromagnets similar to other magnets?

Tju [1.3M]

Answer:a As the name suggests, a permanent magnet is 'permanent'. ... An electromagnet is made from a coil of wire which acts as a magnet when an electric current passes through it. Often an electromagnet is wrapped around a core of ferromagnetic material like steel, which enhances the magnetic field produced by the coil.... hope these helps chu :/

Explanation:

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2 years ago

Two copper pennies has a mass of 6.64g how many moles of copper do they contain

Ann [662]

Answer:

It contains 0.105 mole cu

Explanation:

3 0

3 years ago

Please help: A 0.200 M NaOH solution was used to titrate a 18.25 mL HF

algol [13]

The molar concentration of the original HF solution : 0.342 M

Further explanation

Given

31.2 ml of 0.200 M NaOH

18.2 ml of HF

Required

The molar concentration of HF

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence (amount of H⁺/OH⁻, for NaOH and HF n =1)

Titrant = NaOH(1)

Titrate = HF(2)

Input the value :

$\tt 0.2\times 31.2\times 1=M_2\times 18.25\times 1\\\\M_2=0.342$

7 0

3 years ago

How many grams of zinc would be required to produce 9.65g of zinc hydroxide

Effectus [21]

The question is incomplete, here is the complete question:

How many grams of zinc would be required to produce 9.65g of zinc hydroxide

Zn+2MnO₂+H₂O→Zn(OH)₂+Mn₂O₃

Answer: The mass of zinc required is 6.35 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of zinc hydroxide = 9.65 g

Molar mass of zinc hydroxide = 99.4 g/mol

Putting values in equation 1, we get:

$\text{Moles of zinc hydroxide}=\frac{9.65g}{99.4g/mol}=0.0971mol$

The given chemical equation follows:

$Zn+2MnO_2+H_2O\rightarrow Zn(OH)_2+Mn_2O_3$

By Stoichiometry of the reaction:

1 mole of zinc hydroxide is produced from 1 mole of zinc

So, 0.0971 moles of zinc hydroxide will be produced from = $\frac{1}{1}\times 0.0971=0.0971mol$ of zinc

Now, calculating the mass of zinc from equation 1, we get:

Molar mass of zinc = 65.4 g/mol

Moles of zinc = 0.0971 moles

Putting values in equation 1, we get:

$0.0971mol=\frac{\text{Mass of zinc}}{65.4g/mol}\\\\\text{Mass of zinc}=(0.0971mol\times 65.4g/mol)=6.35g$

Hence, the mass of zinc required is 6.35 grams

6 0

3 years ago