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S_A_V [24]
4 years ago
14

Injuries can be prevented if you follow the rules, use protective equipment, and know the risks of injuries involved in each spo

rt. Please select the best answer from the choices provided. T F
Physics
2 answers:
My name is Ann [436]4 years ago
8 0

Answer:

The given statement is true

Explanation:

Injuries are the ones that cut skin, tissues. Injuries include cuts, scratches, scrapes and punctured skin and worst case is fatal.

Normally injury is caused by external force, includes damages done to the body.

Definitely injuries can be prevented if rules are followed, protective equipments are used.  Also in each sport, risks of injuries if known measures can be taken to prevent the injuries

The given statement is true

padilas [110]4 years ago
4 0

Answer:

this statement is true.


Injuries can be prevented if you follow the rules, use protective equipment, and know the risks of injuries involved in each sport.

injuries can be prevented if we follow the rules and know the risk of injuries because there’s a very famous proverb “prevention is better than cure”.


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The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103
Tju [1.3M]

Answer:

2.0 × 104 2.0

7 0
3 years ago
What is the "address" of the earth in the Cosmo
tino4ka555 [31]
This inaugural journey may be slow-going for those who already know their way around the solar system, as our place in it is explained by a “cosmic address” (Earth<span>, solar system, Milky Way, local group, Virgo supercluster, observable universe), but interest will be held by the sharp and mesmerizing graphics.</span>
6 0
4 years ago
A force of 5N and a force of 8N act to the same point and are inclined at 45degree to each other. Find the magnitude and directi
Alex_Xolod [135]
  • Magnitude: 12.1 N.
  • Direction: 17.0° to the 8 N force.
<h3>Explanation</h3>

Refer to the diagram attached (created with GeoGebra). Consider the 5 N force in two directions: parallel to the 8 N force and normal to the 8 N force.

  • \displaystyle F_{\text{1, Parallel}} = F_1 \cdot \cos{45^\textdegree} = \dfrac{5\sqrt{2}}{2}\;\text{N}.
  • \displaystyle F_{\text{1, Normal}} = F_1 \cdot \sin{45^\textdegree} = \dfrac{5\sqrt{2}}{2}\;\text{N}.

The sum of forces on each direction will be the resultant force on that direction:

  • Resultant force parallel to the 8 N force: (8 + \dfrac{5\sqrt{2}}{2})\;\text{N}.
  • Resultant force normal to the 8 N force: \dfrac{5\sqrt{2}}{2}\;\text{N}.

Apply the Pythagorean Theorem to find the magnitude of the resultant force.

\displaystyle \Sigma F = \sqrt{{(8 + \dfrac{5\sqrt{2}}{2})}^2 + {(\dfrac{5\sqrt{2}}{2})}^2} = 12.1\;\text{N} (3 sig. fig.).

The size of the angle between the resultant force and the 8 N force can be found from the tangent value of the angle. Tangent of the angle:

\displaystyle \dfrac{\Sigma F_\text{Normal}}{\Sigma F_\text{Parallel}} = \dfrac{8 + \dfrac{5\sqrt{2}}{2}}{\dfrac{5\sqrt{2}}{2}} \approx 0.306491.

Find the size of the angle using inverse tangent:

\displaystyle \arctan{ \dfrac{\Sigma F_\text{Normal}}{\Sigma F_\text{Parallel}}} = \arctan{0.306491} = 17.0\textdegree.

In other words, the resultant force is 17.0° relative to the 8 N force.

4 0
3 years ago
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 1.0 ft/s,
natka813 [3]

Answer:

The angle's rate of change is: -0.125 (degree/feet).

Explanation:

In this case of problem we need to find the angle's rate (α) of change when x=6 ft. First we need to relate (α) with x and y and the expression that do it is: \alpha =Arctan(\frac{y}{x}) where (α) is the angle between the ladder and the ground, x is the horizontal distance and y the vertical distance, now we need to have the variable y at function of x, so we can do it using the Pythagorean theorem and gets:y^{2} +x^{2} =10^{2} solving for y(x) we get:y(x)=\sqrt{100-x^{2}}. Replacing all we have got in the first equation: \alpha =Arctan(\frac{\sqrt{100-x^{2} } }{x}). Finally we derivate this equation at function of variable x and gets this result:\frac{d\alpha }{dx} =\frac{-1}{\sqrt{100-x^{2} } } evaluating at x=6 ft we get: -0.125(degree/feet). The negative signal means that the angle is decreasing.

4 0
3 years ago
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iragen [17]
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4 0
3 years ago
Read 2 more answers
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