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3 years ago

The is the time it takes for a wave to complete one cycle.

Physics

2 answers:

musickatia [10]3 years ago

8 0

Answer:

Period

Explanation:

The period of a wave by definition "is the time it takes to complete one cycle"

We can see the concept of period on the figure attached.

Is the time required to go from at some reference level to the same level or complete one complete cycle. And is defined as:

$T= \frac{1}{f}$

Where f is the frequency. And is also defined as:

$T =\frac{\lambda}{v}$

Where $\lambda$ is the wavelength for the wave and v the velocity.

hichkok12 [17]3 years ago

3 0

Answer:

Time Period

Explanation:

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Rank the pressures from highest to lowest:

n200080 [17]

Answer:

P₃ > P₁ > P₂

Explanation:

To rank pressure of the given situation

a) we know

Pressure at height h below

P = ρ g h

density of salt water, ρ = 1029 kg/m³

P₁ = 1029 x 10 x 0.2

P₁ = 2058 Pa

b) density of fresh water, ρ = 1000 kg/m³

P₂ = 1000 x 10 x 0.2

P₂ = 2000 Pa

c) density of mercury, ρ = 13593 kg/m³

P₃ = 13593 x 10 x 0.05

P₃ = 6796.5 Pa

Rank of Pressures from highest to lowest

P₃ > P₁ > P₂

3 0

3 years ago

A block of mass m sits at rest on a rough inclined ramp that makes an angle θ with the horizontal. What must be true about force

nignag [31]

Answer:

Option B

Explanation:

For a system of block on inclined ramp shown in the attached image. From the attached image, the Normal force N, weight mg and frictional force f act on the block. The sum of vertical forces should be zero just as sum of vertical forces should be zero when the system is in equilibrium condition.

Taking sum of forces along the inclined plane we deduce that

[tex]f=mgsin \theta [tex]

Therefore, option B is the correct option.

8 0

3 years ago

calcula el potencial electrico de un punto B que se encuentra a 75cm de una varga positica q=9×10-6c

ankoles [38]

Answer:

V = 72000 volts

Explanation:

calculates the electric potential of a point B that is 75cm from a positive charge q = 9 × 10-6c

Given that,

Electric charge, $q=9\times 10^{-6}\ C$

We need to find the electric potential of a point B that is 75 cm from this charge. The formula for the electric potential is given by :

$V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 6\times 10^{-6}}{0.75}\\\\V=72000\ V$

So, the electric potential is equal to 72000 Volts.

3 0

3 years ago

g A boat is anchored 2000 ft from shore anddirects its searchlight towards an automobile travelingdown the straight road. At the

Darya [45]

Answer:

Explanation:

The distance of searchlight will act as radius R and velocity of car may be supposed to be tangential velocity v . We are required to calculate angular velocity ω .

v = 80 ft /s

R = 3000 ft

ω = v / R

= 80 / 3000 = .027 rad / s

For angular acceleration the formula is

angular acceleration α = a / R

a is linear acceleration = 15 ft / s²

α = 15 / 3000 = .005 rad / s².

3 0

3 years ago

A student tosses a ball horizontally from a balcony to a friend 3.8 meters down below them. How long does the ball take to reach

Vsevolod [243]

Answer:

The time it takes the ball to fall 3.8 meters to friend below is approximately 0.88 seconds

Explanation:

The height from which the student tosses the ball to a friend, h = 3.8 meters above the friend

The direction in which the student tosses the ball = The horizontal direction

Given that the ball is tossed in the horizontal direction, and not the vertical direction, the initial vertical component of the velocity of the ball = 0

The equation of the vertical motion of the ball can therefore, be represented by the free fall equation as follows;

h = 1/2 × g × t²

Where;

g = The acceleration due gravity of the ball = 9.81 m/s²

t = The time of motion to cover height, h

Then height is already given as h = 3.8 m

Substituting gives;

3.8 = 1/2 × 9.81 × t²

t² = 3.8/(1/2 × 9.81) ≈ 0.775 s²

∴ t = √0.775 ≈ 0.88 seconds

The time it takes the ball to fall 3.8 meters to friend below is t ≈ 0.88 seconds.

8 0

3 years ago