Answer: 2200J
Explanation:
M = 44kg
V = 10m/s
K.E =?
K.E = 1/2MV2 = 1/2 x 44 x (10)^2
K.E = 22 x 100
K.E = 2200J
Answer:
22425 J
Explanation:
From the question,
Applying
Q = cm(t₂-t₁).................. Equation 1
Where Q = Thermal Energy, c = specific heat capacity of aluminium, m = mass of aluminium, t₂ = Final Temperature, t₁ = Initial Temperature.
Given: c = 897 J/kg.K, m = 1.0 kg, t₁ = 50 °C, t₂ = 25 °C (The final temperature is reduced by half)
Substitute these values into equation 1
Q = 897×1×(25-50)
Q = 897×(-25)
Q = -22425 J
Hence the thermal energy lost by the aluminium is 22425 J
Answer:
It takes about 88 seconds for the cannonball to reach its maximum height (ignoring air resistance).
Explanation:
Answer:
yes
Explanation:
because it is independent of eachother
The reverberation time with 800 audiences is 0.875 seconds.
<h3>
Reverberation time with 800 audience</h3>
R₁V₁ = R₂V₂
where;
- R₁ is the reverberation time with 400 audience
- R₂ is the reverberation time with 800 audience
- V₁ is initial volume
- V₂ is final volume
R₂ = R₁V₁/V₂
R₂ = (1.4 x 500) / 800
R₂ = 0.875 seconds
Thus, the reverberation time with 800 audiences is 0.875 seconds.
Learn more about reverberation time here: brainly.com/question/9278479
#SPJ1