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3 years ago

How does stress influence our immune system?

Physics

2 answers:

KengaRu [80]3 years ago

6 0

Answer:

When you experience prolonged stress, your body needs those T-cells and white blood cells, and unfortunately, cortisol continues to suppress them, thus weakening your immune system over time.

Explanation:

Stress, Illness and the Immune System. ... When we're stressed, the immune system's ability to fight off antigens is reduced. That is why we are more susceptible to infections. The stress hormone corticosteroid can suppress the effectiveness of the immune system

Fed [463]3 years ago

4 0

Answer:

stress makes our immune system worse

Explanation:

stress releases hormones which tells the body we are in danger, and makes the body put all the attention to the defense mechanisms. Because the energy is taken away from then immune system, it leaves it weak, and an easy targets to sickness and injuries to take control

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A 69.5-kg person throws a 0.0475-kg snowball forward with a ground speed of 31.5 m/s. A second person, with a mass of 57.5 kg, c

Leno4ka [110]

Answer:

- After throwing the snow, velocity of the thrower is 2.33 m/s

- the velocity of the receiver is 0.026 m/s

Explanation:

Given the data in the question;

Using conservation of momentum,

Initial thrower has a momentum of mv; $m_{total$ v

(69.5 kg + 0.0475 kg) × 2.35 m/s = 163.4366 kg.m/s

Now, When he throws it at 31.5 m/s, these constitutes a momentum of;

(0.0475 kg )(31.5 m/s) = 1.49625 kg.m/s

hence his momentum now is: 163.4366 - 1.49625 = 161.94035 kg.m/s

To get his velocity, we say;

161.94035 = mv

{ he lost weight of the snow ball so, m = 69.5 kg )

161.94035 = 69.5 × v

v = 161.94035 / 69.5

v = 2.33 m/s

Therefore, After throwing the snow, velocity of the thrower is 2.33 m/s

Next is the Receiver;

the receiver will gain momentum of 1.49625 kg.m/s

he has no momentum initially and after he catches the snow ball;

1.49625 kg.m/s = mv

1.49625 kg.m/s = ( 57.5 kg + 0.0475 kg ) × v

1.49625 kg.m/s = 57.5475 kg × v

v = ( 1.49625 kg.m/s ) / 57.5475 kg

v = 0.026 m/s

Therefore, the velocity of the receiver is 0.026 m/s

3 0

3 years ago

Find the ratio of the diameter of iron to copper wire, if they have the same resistance per unit length (as they might in househ

Natasha_Volkova [10]

Answer:

The ratio of the diameter of iron to Cu is;

$\frac{d{Fe} }{ d{Cu} } =\sqrt{\frac{p_{Fe} }{ p_{Cu} }}$

Explanation:

R=(ρL)/A

R is resistance,
L is length,
A is area,
ρ is resistivity
d is diameter

from the question the two materials have the same resistance per unit length.

$\frac{R}{L}= \frac{p}{A}$

$\frac{R}{L}$ for iron = $\frac{R}{L}$ for copper

This means we can equate ρ/A for both materials.

$\frac{p_{Fe} }{A_{Fe} } =\frac{p_{Cu} }{A_{Cu} }$

re-arranging the equation we have,

$\frac{A_{Fe}}{A_{Cu} } =\frac{p_{Fe} }{ p_{Cu} }$

$A=\pi \frac{d^{2} }{4}$

$\frac{A_{Fe}}{A_{Cu} } =\frac{d^{2}{Fe} }{ d^{2}{Cu} }$

$\frac{d^{2}{Fe} }{ d^{2}{Cu} } =\frac{p_{Fe} }{ p_{Cu} }$

$\frac{d{Fe} }{ d{Cu} } =\sqrt{\frac{p_{Fe} }{ p_{Cu} }}$

5 0

3 years ago

We can calculate the force that the atmospheric pressure produces on a surface. Consider a living room that has a 4.0m×5.0m floo

qaws [65]

Answer:

Force, $F=2.02\times 10^6\ N$

Explanation:

It is given that,

Length of the room, l = 4 m

breadth of the room, b = 5 m

Height of the room, h = 3 m

Atmospheric pressure, $P=1\ atm=101325\ Pa$

We know that the force acting per unit area is called pressure exerted. Its formula is given by :

$P=\dfrac{F}{A}$

$F=P\times l\times b$

$F=101325\times 4\times 5$

$F=2.02\times 10^6\ N$

So, the total force on the floor due to the air above the surface is $2.02\times 10^6\ N$ . Hence, this is the required solution.

4 0

2 years ago

The total potential and kinetic energy of all the microscopic particles in an object make up its

Fofino [41]

The total potential and kinetic energy of all the microscopic particles in an object make up its <span>B. thermal energy. </span>

7 0

3 years ago

Read 2 more answers

A mass m is placed at the rim of a frictionless

olchik [2.2K]

Answer:

Explanation:

at collision, m has a velocity of √2gR

The center of mass of the system has a velocity of

m(√2gR) + 3m(0) = (m + 3m)v

v = ¼√2gR

The stationary mass (3m) will depart at twice the system center of mass velocity

v(3m) = ½√2gR ANSWER B

The relative velocity before the collision will be the negative of the relative velocity after the collision.

v(m) = ½√2gR - √2gR = -½√2gh ANSWER A

m will rise to a height of v²/2g = (-½√2gR)²/2g = 0.25R

7 0

2 years ago