distance from the Sun of 2.77 astronomical units or about 414 million km 257 million miles and orbiting period of 4.62 years
Answer:
Following are the answer to this question:
Explanation:
In option (a):
- The principle of Snells informs us that as light travels from the less dense medium to a denser layer, like water to air or a thinner layer of the air to the thicker ones, it bent to usual — an abstract feature that would be on the surface of all objects. Mostly, on the contrary, glow shifts from a denser with a less dense medium. This angle between both the usual and the light conditions rays is referred to as the refractive angle.
- Throughout in scenario, the light from its stars in the upper orbit, the surface area of both the Earth tends to increase because as light flows from the outer atmosphere towards the Earth, it defined above, to a lesser angle.
In option (b):
- Rays of light, that go directly down wouldn't bend, whilst also sun source which joins the upper orbit was reflected light from either a thicker distance and flex to the usual, following roughly the direction of the curve of the earth.
- Throughout the zenith specific position earlier in this thread, astronomical bodies appear throughout the right position while those close to a horizon seem to have been brightest than any of those close to the sky, and please find the attachment of the diagram.
Answer:
13.33 seconds
Explanation:
At maximum height, the equation of motion becomes:
<em> v = u + at</em>
Since the object was thrown vertically, the initial velocity (u) is zero and the acceleration (a) becomes the acceleration due to gravity (10 m/s2). The equation becomes:
<em>v = at</em>
<em>v = 480 k</em>m/hr = 133.333 m/s
10t = 133.333
t = 133.333/10
t = 13.33 seconds.
<em>The time for the ball thrown vertically with a velocity of 480 km/hr to reach the maximum height is </em><em>13.33 seconds</em><em>.</em>
Answer:
Part a)

Part b)

Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass
Explanation:
Part a)
Let say the collision between Moose and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part b)
Let say the collision between Camel and the car is elastic collision
So here we can use momentum conservation


also by elastic collision condition we know that

now we have

now we have

Now loss in kinetic energy of the car is given as


so fractional loss in energy is given as



Part c)
So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass