Answer:
0.056 psi more pressure is exerted by filled coat rack than an empty coat rack.
Explanation:
First we find the pressure exerted by the rack without coat. So, for that purpose, we use formula:
P₁ = F/A
where,
P₁ = Pressure exerted by empty rack = ?
F = Force exerted by empty rack = Weight of Empty Rack = 40 lb
A = Base Area = 452.4 in²
Therefore,
P₁ = 40 lb/452.4 in²
P₁ = 0.088 psi
Now, we calculate the pressure exerted by the rack along with the coat.
P₂ = F/A
where,
P₂ = Pressure exerted by rack filled with coats= ?
F = Force exerted by filled rack = Weight of Filled Rack = 65 lb
A = Base Area = 452.4 in²
Therefore,
P₂ = 65 lb/452.4 in²
P₂ = 0.144 psi
Now, the difference between both pressures is:
ΔP = P₂ - P₁
ΔP = 0.144 psi - 0.088 psi
<u>ΔP = 0.056 psi</u>
The time it takes for a ball to complete the trip is given to be 4.10 s. This implies that the trip going up of the ball is equal to 2.05 s. Using this time to determine the initial speed, we have,
Vf = Vo - gt
Vf is the final speed which is equal to 0 on the topmost location of the ball.
0 = Vo - (9.8 m/s²)(2.05 s)
Vo = 20.09 m/s
At 0.5 s,
Vf = 20.09 m/s - (9.8 m/s²)(0.5 s)
Vf = 15.19 m/s
Thus, the speed of the ball when the height is in level with the top of the flagpole is 15.19 m/s.
Answer:
The answer is the shirt would disappear because I would eat him
Answer:
The critical angle is 
Explanation:
From the question we are told that
The refractive index of the core is 
The refractive index of the cladding is 
Generally according to Snell's law
Here for total internal reflection the refractive angle is 
and the critical angle is equal to the critical angle so 
substituting values
![\theta_c = sin^{-1} [\frac{1.21}{1.35} ]](https://tex.z-dn.net/?f=%5Ctheta_c%20%20%3D%20sin%5E%7B-1%7D%20%5B%5Cfrac%7B1.21%7D%7B1.35%7D%20%5D)
