1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Paul [167]
3 years ago
5

A ball having a mass of 200 g is released from rest at a height of 400 mm above a very large fixed metal surface. If the ball re

bounds to a height of 325 mm above the surface, determine the coefficient of restitution between the ball and the surface.
Physics
1 answer:
AysviL [449]3 years ago
5 0

Answer:

0.9

Explanation:

h = 400 mm, h' = 325 mm

Let the coefficient of restitution be e.

h' = e^2 x h

325 = e^2 x 400

e^2 = 0.8125

e = 0.9

You might be interested in
Two security professionals - Jo and Chris - are discussing the contracting process.
UNO [17]
Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
5 0
3 years ago
NEED HELP ASP<br> WILL GIVE POINTS OR WHATEVER
solniwko [45]

Answer:

you need to multiply the momentum and the mass

8 0
3 years ago
How does surface area affect the amount of air resistance an object experiences?
Ymorist [56]
The greater the cross-sectional area of an object, the greater the amount of air resistance it encounters since it collides with more air molecules. ... It will have to accelerate for a longer period of time before there is enough upward air resistance to balance the downward force of gravity.
6 0
3 years ago
Explain the relationship between resistance and the velocity of shortening.
butalik [34]
The velocity of shortening refers to the speed of the contraction from the muscle shortening while lifting a load. The relationship between the resistance and velocity of shortening is inverse. The greater the resistance, the shorter the velocity of shortening and the smaller the resistance, the larger the velocity of shortening.

Hopefully this help :)
7 0
3 years ago
A spherical bowling ball with mass m = 4.1 kg and radius R = 0.117 m is thrown down the lane with an initial speed of v = 8.9 m/
weqwewe [10]

Answer:Given mass = 4.1kg

Radius = 0.0117m

Velocity V = 8.4m/s

Coefficient of friction = 0.25

Explanation: Below is an attached solution to the problem stated above.

1. The angular acceleration is equal to 524rad/s^2

2. The linear acceleration is equal to 2.45m/s^2

3.the time it takes the ball to begin rolling = 0.98s

4. The distance the ball slides before it begins to roll = 7.05m

3 0
3 years ago
Other questions:
  • During the expansion of the early universe, which two interactions were the last to separate? a. the strong and weak interaction
    12·1 answer
  • You are driving on the interstate and see a sign that says the speed limit is 50 miles per hour.
    9·2 answers
  • According to the condensation theory, the most important factor for the formation of our planets was _____. the gravitational pu
    5·2 answers
  • What kind of energy involves the flow of positive charges?
    9·2 answers
  • On the moon the surface temperature ranges from 379 K during the day to 1.04 x 102 K at night. Convert these temperatures to the
    13·1 answer
  • as you kick a soccer ball with 8 m/s at an angle of 40, how long does it take to get to the highest point
    9·1 answer
  • If 1 kg of each substance in the table changes temperature by 15°C, which
    9·2 answers
  • Light of wavelength 505 nm passes through a single slit of width 4.32 x 10-5 m. At what angle does the first interference minimu
    5·1 answer
  • In the picture below, label which particle is the solute and which is the solvent ​
    14·1 answer
  • A 0.144 kg baseball approaches a batter with a speed of . The batter lines the ball directly back to the pitcher with a speed of
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!