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Paul [167]
4 years ago
5

A ball having a mass of 200 g is released from rest at a height of 400 mm above a very large fixed metal surface. If the ball re

bounds to a height of 325 mm above the surface, determine the coefficient of restitution between the ball and the surface.
Physics
1 answer:
AysviL [449]4 years ago
5 0

Answer:

0.9

Explanation:

h = 400 mm, h' = 325 mm

Let the coefficient of restitution be e.

h' = e^2 x h

325 = e^2 x 400

e^2 = 0.8125

e = 0.9

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Answer:

a. Vf = 39.24 [m/s]

b. Vf = 31.24 [m/s]

c. Vf = 47.24 [m/s].

Explanation:

To solve this problem we can use the following equation of kinematics. We have to keep in mind that the gravitational acceleration acts downwards, therefore when the rock falls towards the abyss it has the same direction of the acceleration and that is why the gravitational acceleration has a positive sign in the equation.

v_{f}=v_{o}+g*t

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0 (when the rock is dropped)

g = gravitational acceleration = 9.81 [m/s²]

t = time = 4 [s]

a.

v_{f}=0+9.81*4\\v_{f}= 39.24 [m/s]

b.

In this particular situation, the acceleration will be taken as negative because the gravity is pointing in the opposite direction of the movement of the rock.

v_{f}=8-(9.81*4)\\v_{f}=-31.24[m/s]

The negative sign in the answer tells us that the rock no longer moves up instead it does downwards when 4 seconds have passed.

c.

v_{f}=8+(9.81*4)\\v_{f}=47.24[m/s]

4 0
3 years ago
What is the speed of the object in the graph? Explain​
Nikolay [14]

Answer:

0.8m per second

Explanation:

we measure speed as distance over time

distance=8m

time=10s

therefore speed = 8/10

=0.8m per second

5 0
3 years ago
Read 2 more answers
The maximum torque on a set of 20 square loops with edge lengths of 6 cm in a 4.0 T magnetic field is:A) 0.288 N-m.B) 4.8 N-m.C)
Vesnalui [34]

Answer:

option (D

Explanation:

Torque is given by

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option (D)

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Tasya [4]

Answer:

C) T

Explanation:

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A = Amplitude of the motion

T = Time period of oscillation

k = Spring constant of the spring

A = Amplitude of the motion

Time period of oscillation of the mass attached to the spring is given as

T = 2\pi \sqrt{\frac{M}{k} }

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How is the world do you do this?
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