Answer:
Explanation:
Can you explain a bit further? once u do, ill edit my answer and tell you :) But to use a fidget spinner, u have to put ur thumb at the bottom and index finger at the top, and spin it with you other fingers if thats what you meant
N₂ + 3 H₂ → 2 NH₃
number of moles of N₂ = 38 g / 28 g/mol = 1.357 mol
1 mole of N₂ gives 2 moles of NH₃
1.357 mol of N₂ will give ?? mole NH₃
= 2 x 1.357 = 2.7 mol NH₃
1st and 4th options are suitable answers, as these 2 changes are not exactly physical changes as it cant return back to original form and as well as its not cooling, so I feel its 1st and 4th options
A temperature regime that experiences consistent high temperatures with little seasonality is the <u>equatorial</u>.
<h3>What is temperature regime?</h3>
These systems have a significant impact on how soils are used and managed, especially when choosing plants that are adapted to the environment. There are 10 different soil temperature regimes: cryic, frigid, hyperthermic, isofrigid, isohyperthermic, isomesic, isothermic, mesic, pergelic, and thermic.
<h3>What is a mesic temperature regime?</h3>
Mesic. At a depth of 50 cm from the soil surface or at a dense, lithic, or paralytic contact, whichever is shallower, the difference between the mean summer and mean winter soil temperatures is greater than 6° C and the mean annual soil temperature is 8° C or higher but lower than 15° C.
To know more about temperature regime visit:
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Answer:
- Acid-Base reaction (the reactanct acting as a base is NaOH)
Explanation:
The reaction that takes place is:
- C₃H₅O(CO₂H)₃(aq) + 3OH⁻ (aq) → C₃H₅O(CO₂)₃⁻³(aq) + 3H₂O(l)
This is a <em>acid-base reaction</em>, with the citric acid acting as the acid and the <u>sodium hydroxide NaOH acting as the base.</u>
We <u>calculate the moles of citric acid</u> using the information from the titration:
- 0.0142 L * 0.340 M *
= 1.609x10⁻³ mol citric acid
Now we <u>convert moles to mass</u> using the acid's molecular weight (192.13g/mol):
- 1.609x10⁻³ mol citric acid * 192.13g/mol = 0.3092 g citric acid
Finally we calculate the mass percent of citric acid in the sample:
- 0.3092 g / 16.00 g * 100% = 1.93%
