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lana [24]
3 years ago
9

A(n) ________ is a device that measures a change in speed

Chemistry
2 answers:
jok3333 [9.3K]3 years ago
5 0

Answer:

C Accelerometer

Explanation:

An accelerometer is an electromechanical device used to measure acceleration forces. Such forces may be static, like the continuous force of gravity or, as is the case with many mobile devices, dynamic to sense movement or vibrations. Acceleration is the measurement of the change in velocity, or speed divided by time.

Hpoe this Helps!

daser333 [38]3 years ago
5 0
The answer is C: accelerometers
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Licemer1 [7]

Answer:

B. Yes, because the mass of all the products of burning is equal to the mass

of the reactants (wood and oxygen gas).

Explanation:

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3 0
3 years ago
Balance the following chemical equations
grigory [225]

Answer:

1. 2,3,2

2. 4,5,2

3. 3,1,1

Explanation:

7 0
2 years ago
If Maria winks exactly 5 times every minute and she sleeps
Elina [12.6K]

First, we need to find the amount of winks in an hour, to simplify it so we can answer easier. Since there are 60 minutes in an hour, we can multiply 5 by 60 to find the number of winks in an hour.

5*60=300

Now multiply 300 by 8.

300*8=2,400

She winks exactly 2,400 times per day.

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4 0
3 years ago
Read 2 more answers
How many milliseconds (ms) are there in 3.5 seconds (s)?
ivolga24 [154]

Answer:

13 hundred

Explanation:

4 0
3 years ago
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A sample of oxygen gas has a volume of 3.24 L at 29°C. What volume will it occupy at 104°C if the pressure and number of mol are
ohaa [14]

<u>Answer:</u> The final volume of the oxygen gas is 4.04 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.24L\\T_1=29^oC=(29+273)K=302K\\V_2=?\\T_2=104^oC=(104+273)K=377K

Putting values in above equation, we get:

\frac{3.24L}{302K}=\frac{V_2}{377K}\\\\V_2=4.04L

Hence, the final volume of the oxygen gas is 4.04 L

8 0
3 years ago
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