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Ahat [919]
3 years ago
11

A cheetah can accelerate from rest at the rate of 4m /s

Physics
1 answer:
lesya [120]3 years ago
6 0
Acceleration of cheetah (a) = 4m/s²
time = 10s
initial velocity(u) = 0
final velocity = v
distance travelled = s

v = u +at = 0 + 10×4 = 40m/s
s = (v²-u²)/2a = 40²/(2×4) = 1600/8 = 200m
   
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Answer:

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Explanation:

The diffraction phenomenon is described by the equation

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The diffraction measurements are made on a screen that is far from the slit, and the angles in the experiment are very small, let's use trigonometry

          tan θ = y / L

          tan θ = sint θ / cos θ≈ sin θ

We substitute in the first equation

           a (y / L) = m λ

The first maximum occurs for m = 1

The distance is measured from the center point of maximum, which coincides with the center of the slit, in this case the distance is the total width of the central maximum, so the distance (y) measured from the center is

         y = 1.15 / 2 = 0.575 cm

         y = 0.575 10⁻² m

Let's clear the distance to the screen (L)

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Let's calculate

     L = 115 10⁻⁶  0.575 10⁻² / 575 10⁻⁹

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3 0
3 years ago
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