Answer:
Step-by-step explanation:
I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.
..
let quarters be x
dimes = x+2
...
dimes + quarters = x+x+2=2x+2
...
nickels = 30-(2x+2)
...
5(30-(2x+2))+10(x+2)+25x=460
5(30-2x-2)+10x+20+25x=460
150-10x-10+10x+20+25x=460
160+25x=460
-160
25x=460-160
25x=300
/25
x=300/25
x=12 ---- quarters
x+2= 12+2=14 dimes
30-(2x+2)=4 nickels
...
check
4*5+14*10+12*25=20+140+300=460
Answer:
n = 12.3
Step-by-step explanation:
I'm assuming we're looking for n, to find it, we need to isolate it.
Our equation will be solved through PEMDAS :
Parenthesis
Exponent
Multiply/Divide
Add/Subtract
n / 10^2 = 0.123
Get rid of the exponent by applying it to 10,
10^2 = 100
n/100 = 0.123
Now to get rid of the division, multiply the denominator (100) to both sides.
n/100 * 100 = 0.123 * 100
n = 12.3
1 /5 = 0 . 2
45 * . 2 = 9
Hope this helped :)
The answers should be 1D, 2C, 3B, 4A, and 5A.
Answer:
(a) -7, (b) 2
Step-by-step explanation:
a) When x = 0,
=> x² - 8x - 7
=> (0)² - 8(0) - 7
=> 0 - 0 - 7
=> - 7
b) When x = -1,
=> x² - 8x - 7
=> (-1)² - 8(-1) - 7
=> 1 + 8 - 7
=> 9 - 7
=> 2
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em>
