What type of molecule is acetylacetone?

A 8.65-L container holds a mixture of two gases at 11 °C. The partial pressures of gas A and gas B, respectively, are 0.205 atm

Vsevolod [243]

The total pressure = 1.402 atm

calculation

Total pressure = partial pressure of gas A + partial pressure of gas B + partial pressure of third gas

partial pressure of gas A= 0.205 atm

Partial pressure of gas B =0.658 atm

partial pressure for third gas is calculated using ideal gas equation

that is PV=nRT where,

p(pressure)=? atm

V(volume) = 8.65 L

n(moles)= 0.200 moles

R(gas constant)=0.0821 L.atm/mol.k

T(temperature) = 11°c into kelvin =11+273 =284 k

make p the subject of the formula by diving both side by V

p =nRT/v

p = [(0.200 moles x 0.0821 L.atm/mol.K x 284 K)/8.65L)] =0.539 atm

Total pressure is therefore = 0.205 atm +0.658 atm +0.539 atm

=1.402 atm

6 0

3 years ago

HELPPPPPP PLEASE :(((((((((((((((((

iogann1982 [59]

Answer:

A. The cup would go forward.

Explanation:

Everything in the car is traveling at the speed of the car. So when making a sudden stop, whatever isn't restrain in place, will continue to move forward. Something like that will usually happen if you don't wear a seat belt in a car.

7 0

3 years ago

Calculate the mass of aluminum that would have the same number of atoms as 6.35 g of cadmium

Sergeu [11.5K]

Answer:

1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.

Explanation:

Given data:

mass of cadmium = 6.35 g

Number of atoms of aluminum as 6.35 g cadmium contain = ?

Solution:

Number of moles of cadmium = 6.35 g/ 112.4 g/mol

Number of moles of cadmium = 0.06 mol

Number of atoms of cadmium:

1 mole = 6.022×10²³ atoms of cadmium

0.06 mol × 6.022×10²³ atoms of cadmium/ 1mol

0.36×10²³ atoms of cadmium

Number of atoms of Al:

Number of atoms of Al = 0.36×10²³ atoms

1 mole = 6.022×10²³ atoms

0.36×10²³ atoms × 1 mol /6.022×10²³ atoms

0.06 moles

Mass of aluminum:

Number of moles = mass/molar mass

0.06 mol = m/ 27 g/mol

m = 0.06 mol ×27 g/mol

m = 1.62 g

Thus, 1.62 g of Al contain the same number of atoms as 6.35 g of cadmium have.

6 0

3 years ago

Which formula should be used to calculate pressure and temperature changes if the volume remains constant

svlad2 [7]

Answer:

P1 /T1 =P2/T2

Explanation:

ccording to the Gay- Lussac's Law,

" The pressure of given amount of gas is directly proportional to the temperature at a constant volume"

Mathematical expression:

P ∝ T

P = CT

P / T = C

As the temperature increase, the pressure also increase and vice versa.

The initial and final expression of volume and pressure can be written as,

P₁ / T₁ = P₂ / T₂

8 0

4 years ago

The element europium exists in nature as two isotopes: 151eu has a mass of 150.9196 amu, and 153eu has a mass of 152.9209 amu. t

Ratling [72]

Two isotopes of europium are 151eu and 153eu

Mass of 151eu = 150.9196 amu

Mass of 153eu = 152.9209 amu

Average atomic mass = 151.96 amu

Let x and y are the relative abundance of two isotopes of europium are 151eu and 153eu

So, x% times 150.9196 + y% times 152.9209 = 151.96

x150.9196 + y152.9209 = 151.96

And x + y = 100% = 1, from here x = 1 – y and y = 1 - x

Solve these equation by substitution,

By replacing x = 1-y, we get

(1-y)150.9196 + y152.9209 = 151.96

150.9196 – 150.9196y + y152.9209 = 151.96

2.0013y = 1.0404

Y =0.5199 = 51.99%

Using the value of y we get,

X = 1-y = 1-51.99 = 0.4801 = 48.01%

So, relative abundance of two isotopes of europium are 151eu and 153eu are 48.01% and 51.99% respectively

6 0

3 years ago

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