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castortr0y [4]
3 years ago
7

The X-ray source Cygnus X-1 has a mass of at least 11 solar masses and a diameter of only about one-quarter the diameter of the

Earth. With such a small diameter it must be a compact object, and with such a large mass it can't be a white dwarf or a neutron star, so a black hole is the only possibility remaining. How was the diameter of Cygnus X-1 found
Physics
1 answer:
SOVA2 [1]3 years ago
7 0

Answer:

Answer is It was deduced from the rate at which it glimmers.

Refer below.

Explanation:

The X-ray source Cygnus X-1 has a mass of at least 11 solar masses and a diameter of only about one-quarter the diameter of the Earth. With such a small diameter it must be a compact object, and with such a large mass it can't be a white dwarf or a neutron star, so a black hole is the only possibility remaining. The diameter of Cygnus X-1 found:

It was deduced from the rate at which it glimmers.

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Helpp me pleassee....
lilavasa [31]

Answer:

The fundamental wavelength of the vibrating string is 1.7 m.

Explanation:

We have,

Velocity of wave on a guitar string is 344 m/s

Length of the guitar string is 85 cm or 0.85 m

It is required to find the fundamental wavelength of the vibrating string. The fundamental frequency on the string is given by :

f=\dfrac{v}{2l}\\\\f=\dfrac{344}{2\times 0.85}\\\\f=202.35\ Hz

Now fundamental wavelength is :

\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{344}{202.35}\\\\\lambda=1.7\ m

So, the fundamental wavelength of the vibrating string is 1.7 m.

4 0
3 years ago
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miss Akunina [59]

Answer:

extensions.

Explanation:

Hope this helps

8 0
3 years ago
Read 2 more answers
The index of refraction of Sophia's cornea is 1.387 and that of the aqueous fluid behind the cornea is 1.36. Light is incident f
shtirl [24]

Answer:

17.85°

Explanation:

To find the angle to the normal in which the light travels in the aqueous fluid you use the Snell's law:

n_1sin\theta_1=n_2sin\theta_2

n1: index of refraction of Sophia's cornea = 1.387

n2: index of refraction of aqueous fluid = 1.36

θ1: angle to normal in the first medium = 17.5°

θ2: angle to normal in the second medium

You solve the equation (1) for θ2, next, you replace the values of the rest of the variables:

\theta_2=sin^{-1}(\frac{n_1sin\theta_1}{n_2})\\\\\theta_2=sin^{-1}(\frac{(1.387)(sin17.5\°)}{1.36})=17.85\°

hence, the angle to normal in the aqueous medium is 17.85°

7 0
3 years ago
What is it’s vertical distance below the top of the cliff ?
MakcuM [25]

Answer:

It should be 1 meter, but I'm no scientist.

Explanation: IDK

7 0
3 years ago
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dsp73

The horizontal component of velocity is

(22 m/s) • cosine(62°).

The vertical component of velocity is

(22 m/s) • sine(62°).

These are the original components, right after the kick. As time goes on, the horizontal one doesn't change. But the vertical one gets bigger and bigger, because gravity is accelerating the ball downward.

That's the complete story of projectile motion.

7 0
2 years ago
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