Answer:
The molarity of the solution is 245, 2M.
Explanation:
We calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case KCl03) in 1000ml of solution (1 liter):
0,25 L solution----- 61,3 moles of KCl03
1 L solution----x= (1 L solution x 61,3 moles of KCl03)/0,25 L solution
x=245, 2 moles of KCl03 --> <em>The molarity of the solution is 245, 2M</em>
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Answer : The percent-by-mass concentration of acetic acid is, 5.15 %
Explanation : Given,
Mass of acetic acid = 51.80 g
Density of solution = 1.005 g/ml
Volume of solution = 1.000 L = 1000 ml (1 L = 1000 ml)
First we have to calculate the mass of solution.


Now we have to calculate the percent-by-mass concentration of acetic acid.

Now put all the given values in this formula, we get:

Therefore, the percent-by-mass concentration of acetic acid is, 5.15 %