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boyakko [2]
2 years ago
9

Polypeptides contain _______ amino acids joined by peptide bonds.

Physics
2 answers:
sergiy2304 [10]2 years ago
7 0
Polypeptides contain more than 10 amino acids joined by peptide bonds.


kati45 [8]2 years ago
4 0

Answer:

more than ten

Explanation:

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irina1246 [14]

Answer: 2400m

Explanation: 2400m because 600 times 4 equals 2400

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Match the particles with their characteristics,
In-s [12.5K]
Positive charge=proton
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A soccer player kicks a rock horizontally off a 37 m high cliff into a pool of water. If the player hears the sound of the splas
Alchen [17]
<h2>Answer:</h2>

<em><u>(a). 16.741 m/s</u></em>

<em><u>(b). 15.75 m/s</u></em>

<h2>Explanation:</h2>

In the question,

Height of the cliff, h = 37 m

Time taken to reach the sound to us = 2.92 s

Speed of the sound in air at room temperature = 343 m/s

Now,

Let us say the speed of the ball = u m/s

So,

Time taken by the ball to reach at the bottom, t is given by,

t=\sqrt{\frac{2h}{g}}\\t=\sqrt{\frac{2\times 37}{9.8}}\\t=2.747\,s

So,

Splash is heard after = 2.92 s

So,

<u>Time taken by sound to travel the shortest distance along the hypotenuse of the triangle</u> thus formed is,

t = 2.92 - 2.747

t = 0.172 s

Now,

Distance traveled by sound is given by,

Distance=343\times 0.172\\Distance=59.02\,m

So,

In the triangle using the Pythagoras Theorem,

Horizontal distance traveled is,

D=\sqrt{59.02^{2}-37^{2}}\\D=45.99\,m

So,

Speed of throwing of ball is given by,

Distance=Speed\times Time\\45.99=u\times 2.747\\u=16.741\,m/s

<em><u>Therefore, the speed of the ball = 16.741 m/s.</u></em>

(b).

If,

Speed of sound = 331 m/s

So,

<u>Distance traveled by sound</u> is,

Distance=331\times 0.172\\Distance=56.932\,m

So,

Distance traveled in the horizontal by ball is,

Distance=\sqrt{56.932^{2}-37^{2}}\\Distance=43.269\,m

So,

Speed of the ball thrown is given by,

Speed=\frac{Distance}{Time}\\Speed=\frac{43.269}{2.747}\\Speed=15.75\,m/s

<em><u>Therefore, the speed of the ball = 15.75 m/s.</u></em>

8 0
3 years ago
A circular coil consists of N = 410 closely winded turns of wire and has a radius R = 0.75 m. A counterclockwise current I = 2.4
Svetllana [295]

The complete question is;

A circular coil consists of N = 410 closely winded turns of wire and has a radius R = 0.75 m. A counterclockwise current I = 2.4 A is in the coil. The coil is set in a magnetic field of magnitude B = 1.1 T.

a. Express the magnetic dipole moment μ in terms of the number of the turns N, the current I, and radius

R.

b. Which direction does μ go?

Answer:

A) μ = 1738.87 A.m²

B) The direction of the magnetic moment will be in upward direction.

Explanation:

We are given;

The number of circular coils;

N = 410

The radius of the coil;R = 0.75m

The current in the coils; I = 2.4 A

The strength of magnetic field;

B =1.1T

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μ = NIA

Where;

N is number of turns

I is current

A is area

Now, area; A = πr²

So, A = π(0.75)²

Thus,plugging in relevant values, the magnetic dipole moment is;

μ = 410 * 2.4 * π(0.75)²

μ = 1738.87 A.m²

B) According to Fleming's right hand rule, the direction of the magnetic moment comes out to be in upward direction.

7 0
3 years ago
What is the momentum of a 2.0kg ball rolling at 6.0 m/s
irga5000 [103]
Momentum can be defined by the formula p=m*V (where m is mass and V is velocity) so if we plug in these numbers:

p = 2kg * 6m/s
p = 12 kgm/s
4 0
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