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Galina-37 [17]
3 years ago
15

The chemical formula for glucose is C6H12O6. Therefore, four molecules of glucose will have carbon atoms, hydrogen atoms, and ox

ygen atoms.
Physics
2 answers:
bezimeni [28]3 years ago
7 0
<h3><u>Answer;</u></h3>

<em>- 24 carbon atoms, 48 hydrogen atoms and 24 oxygen atoms</em>

<h3><u>Explanation;</u></h3>
  • <em><u>Glucose </u></em>is a simple carbohydrate and a compound that is made of elements carbon, hydrogen and oxygen.
  • One molecules of glucose<em><u> contains six carbon atoms, 12 hydrogen atoms, and six oxygen atoms.</u></em>
  • Therefore, four molecules of glucose will have <em><u>24 carbon atoms, 48 hydrogen atoms and 24 oxygen atoms.</u></em>
  • That is; 4(C₆H₁₂O₆), thus, C = 4×6 =24, H = 4×12 =48, and O = 4×6 =24.
Gekata [30.6K]3 years ago
5 0
If there are 4 molecules of glucose, there will be 24 carbon, 48 hydrogen, and 24 oxygen.
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an incandescent lightbulb has an efficiency of 2.1% and a power of 60 w. how much light energy does the lighbulb produce in 1 se
AveGali [126]

Explanation:

Power output of the bulb:

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E = (1.26 W) (1 s)

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A snake slithered across the sidewalk in between two sign posts. At the first sign post his speed was
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3 years ago
2013 Indianapolis 500 champion Tony Kanaan holds his hand out of his IndyCar while driving through still air with standard atmos
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Answer:

(a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

All answer are reasonable.

Explanation:

Given that,

Speed v₁= 60 mph

Speed v₂ = 225 mph

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(a). We need to calculate the maximum pressure on his hand

Using equation of pressure

P_{1}=P+\dfrac{1}{2}\rho v^2+\rho gh

there, no vertical movement

So, on neglect of height term

P_{1}=P+\dfrac{1}{2}\rho v_{1}^2

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Put the value in the equation

P_{1}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(60\times1.4667)^2)

P_{1}=2126.0\ lb/ft^2

P_{1}=\dfrac{2126.0}{144}

P_{1}= 14.76\ psi

(b). Speed v₂ = 225 mph

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Using equation of pressure

P_{2}=P+\dfrac{1}{2}\rho v_{2}^2

Put the value in the equation

P_{2}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(225\times1.4667)^2)

P_{2}=2246.17\ lb/ft^2

P_{2}=\dfrac{2246.17}{144}

P_{2}= 15.59\ psi

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We need to calculate the maximum pressure on his hand

Using equation of pressure

P_{3}=P+\dfrac{1}{2}\rho v_{3}^2

Put the value in the equation

P_{3}=14.7\times144+\dfrac{1}{2}\times(0.002376\times(235\times1.4667)^2)

P_{3}=2257.93\ lb/ft^2

P_{3}=\dfrac{2257.93}{144}

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According to bernoulli's equation,

If the car increases the velocity the the pressure on the surface of the driver's hand increases.

The pressure from P₁ to P₃ are all near the value of one atmosphere.

So, the pressure difference of one atmosphere is not enough to break the driver's hand.

Hence, (a). The pressure is 14.76 psi.

(b). The pressure is 15.59 psi.

(c). The pressure is 15.68 psi.

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8 0
3 years ago
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Katyanochek1 [597]

Velocity (unit:m/s) of the wave is given with the formula:

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f=1/T , where T is the period of the wave.

In our case: f=1/3

∧=v/f=24m/s/1/3=24*3=72m

5 0
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